Initial speed = 56mph
Final speed = 35mph
Time taken = 6.7seconds...
Converting the time to hour.. Divide by 3600..
= 6.7/3600
=0.00186hour..
Acceleration = v-u/t
a = 35-56/0.00186
a = -11283.6mph²
The negative sign shows that it decelerated...
V² = u²+2as
(35)² = (56)² + 2×-11283.6×s
Where s is the distance covered within that time...
1225 = 3136 - 22567.2s
22567.2s = 3136-1225
22567.2s = 1911
S = 1911/22567.2
S = 0.08468miles...
But at the end of the question we were made to understand that 1miles = 5280ft
Therefore 0.08468miles = (0.08468×5280)ft
= 447. 11feets...
Which is approximately 447ft.....
Hope this helped.... ?
(D) reacts with acids by producing gas bubbles
Or
(A) White Color
420 m of total distance is covered by the skier on travelling from A to D.
Explanation:
As from the picture, it can be seen that first the skier moved from position A to position B. And the distance covered by this movement is 180 m. Then as the skier travels from position B to position C, the distance between these two positions is 140 m from the figure. As distance is a scalar quantity, the direction is not taken into consideration. So only the magnitudes of the distance between those points are added.
Now, the distance between A to B is 180 m and then from B to C is 140 m, atlast from C to D, the distance is given as 100 m.
So, the total distance will be the sum of all the above found distances. Thus, the total distance will be 180+140+100 = 420 m.
As the question is about distance, so no need to write the direction for it.
Thus, the final answer will be 420 m of total distance is covered by the skier on travelling from A to D.
The distance the object travels
Answer:
0.05
Explanation:
Given a variable C which is the product of two variables A, B:

Then the absolute error on C is given by:
where
are the uncertanties on the measure of A, B and C, respectively.
In this problem, the horizontal component of the velocity
is given by

Therefore, the uncertainty on vx is given by:
(1)
where we have:


, so

The uncertainty on
is given by:

where:

and

So

Also,

So, combininb everything into (1), we find:
