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Gnoma [55]
3 years ago
5

NEED HELP ASAP! Write a statement explaining your claim about whether or not the equation is correctly balanced.

Chemistry
2 answers:
cupoosta [38]3 years ago
8 0

Answer:

I think that it it correctly balanced that is my opinion and, because  the way it is set up, that the answer will tell you weather or not it is correctly balanced or not.

Kisachek [45]3 years ago
4 0

Evaluating the number of atoms of each element on the product and reactant side, we can conclude that the student's equation isn't balanced.

<u>Given the chemical reaction</u> :

Al_{4}C_{3} + 6H_{2}O ---> 3CH_{4} + 4Al(OH)_{3}

For a balanced equation, the number of atoms of each element in the product side must be equal to that on the reactant side.

<u>Number of hydrogen</u> :

Reactant side = (6 × 2) = 12

Product side = (6 × 2) + (6 × 2) = 12 + 24 = 24

<em>Product side ≠ reactant side</em> ; Hence, the equation isn't balanced

<u>The balanced equation for the reaction goes thus</u> :

Al_{4}C_{3} + 12H_{2}O ---> 3CH_{4} + 4Al(OH)_{3}

<u>Reactant side</u> :

Al = 4

H = (12 × 2) = 24

O = 12

C = 3

<u>Product side</u> :

H = (6 × 2) + (6 × 2) = 12 + 24 = 24

Al = 4

O = 4 × 3 = 12

C = 3

Therefore, the student's equation isn't balanced, the balanced version of the equation has been given .

Learn more :brainly.com/question/2720947

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For the reaction given below, the frequency factor A is 8.7 1012 s−1 and the activation energy is 63 kJ/mol. NO(g) + O3(g) → NO2
Alex73 [517]

Answer:

K(70°C) = 2213.376 s-1

Explanation:

balanced reaction:

  • NO(g) + O3(g) → NO2(g) + O2(g)

∴ Ea = 63 KJ/mol

∴ A = 8.7 E12 s-1

∴ T = 70°C ≅ 343 K

Arrhenius eq:

  • K(T) = Ae∧(- Ea/RT)

∴ R = 8.314 E-3 KJ/K.mol

⇒ K(70°C) = (8.7 E12 s-1)e∧[-(63)/(8.314 E-3)(343)]

⇒ K(70°C) = (8.7 E12 s-1)*(2.5444 E-10)

⇒ K(70°C) = 2213.376 s-1

6 0
3 years ago
What general rule can be followed when choosing a type of solvent to dissolve a particular solid?
Fittoniya [83]
 <span>the polarity of the solute or the solvent. 

for example: 
oil will not mix with water because oil molecules are nonpolar however water moleculses are polar. so, they will not mix with each other. 

when we put sodium chloride in water, sodium chloride will be easily dissoved. because both sodium chloride and water are polar. 

in other case, if we put sodium chloride and hexane together. sodium chloride will not dissove in hexane, because hexane is a nonpolar solvent. 

finally, if we try to mix hexane and bromine together, they will mix uniformly. because both hexane and bromine are nonpolar. (note: most diatomic molecules are nonpolar, such as hydrogen gas, oxygen gas, chlorine gas, etc. ) 

so just remember, nonpolar and nonpolar will dissovle each other. and polar and polar will dissolve each other.</span>
4 0
4 years ago
A chemist burns 650.0 g of C4H8S2 in excess oxygen, according the following balanced chemical reaction:
Andrews [41]

Answer:

952.2g SO3

Explanation:

Molar mass of C4H8S2 is 120.2363 g/mol

Mol in 750.0g = 750.0/120.2363 = 6.238 mol

1mol C4H8S2 produces 2 mol SO3

6.238 mol will produce 2×6.238 = 12.476 mol SO3

Molar mass SO3 = 32+3×16 = 80.0g/mol

Theoretical yield = 12.476×80.0 = 998.08g

The actual yield is 95.4%

Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced

Hope it will help you.

7 0
3 years ago
metal weighing 6.98 g was heated to 91.29 °C and then put it into 114.84 mL of water (initially at 24.37 °C). The metal and wate
torisob [31]

Answer:

The specific heat of the metal is 10.93 J/g°C.

Explanation:

Given,

For Metal sample,

mass = 6.98 grams

T = 91.29°C

For Water sample,

volume = 114.84 mL

T = 24.37°C.

Final temperature of mixture = 33.54°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that

water sample temperature changed from  24.37°C to 33.54°C and metal sample temperature changed from 91.29°C to 33.54°C.

We have all values, but, here mass of water is not given. It can be found by using the formula

Density = Mass/Volume

Since, density of water = 1 g/mL

we get, Mass = 114.84 grams.

Since specific heat of water is 4.184 J/g°C.

Now substituting all values in (mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

(6.98)(91.29 - 33.54)(Cp) = (114.84)(33.54 - 24.37)(4.184)

solving, we get,

Cp = 10.93 J/g°C.

the specific heat of the metal is 10.93 J/g°C.

7 0
3 years ago
Why doesnt ammonia support combustion?
earnstyle [38]
We need the reading for this I think
4 0
3 years ago
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