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Gnoma [55]
2 years ago
5

NEED HELP ASAP! Write a statement explaining your claim about whether or not the equation is correctly balanced.

Chemistry
2 answers:
cupoosta [38]2 years ago
8 0

Answer:

I think that it it correctly balanced that is my opinion and, because  the way it is set up, that the answer will tell you weather or not it is correctly balanced or not.

Kisachek [45]2 years ago
4 0

Evaluating the number of atoms of each element on the product and reactant side, we can conclude that the student's equation isn't balanced.

<u>Given the chemical reaction</u> :

Al_{4}C_{3} + 6H_{2}O ---> 3CH_{4} + 4Al(OH)_{3}

For a balanced equation, the number of atoms of each element in the product side must be equal to that on the reactant side.

<u>Number of hydrogen</u> :

Reactant side = (6 × 2) = 12

Product side = (6 × 2) + (6 × 2) = 12 + 24 = 24

<em>Product side ≠ reactant side</em> ; Hence, the equation isn't balanced

<u>The balanced equation for the reaction goes thus</u> :

Al_{4}C_{3} + 12H_{2}O ---> 3CH_{4} + 4Al(OH)_{3}

<u>Reactant side</u> :

Al = 4

H = (12 × 2) = 24

O = 12

C = 3

<u>Product side</u> :

H = (6 × 2) + (6 × 2) = 12 + 24 = 24

Al = 4

O = 4 × 3 = 12

C = 3

Therefore, the student's equation isn't balanced, the balanced version of the equation has been given .

Learn more :brainly.com/question/2720947

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droplets of sulfuric acid

Explanation:

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Bond formed by the sharing of electrons between atoms.
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By what factor does [h+ ] change for each ph change? (a) 3.20 units
konstantin123 [22]
When a change in PH = 10^-ΔPH
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change depends on two factor 0.00063 (10^-3.2)and factor 1585 (10^3.2)depending on the way which the change goes.if PH change from PH=0 to PH= 3.2 so the change is decreasing from concentration from 1 mol to 0.00063 and if PH change from PH = 3.2 to PH=0 so the change is increasing by a factor of 1585.
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3 years ago
DUE IN 30 MINUTES!!! (please keep it short if you can, if not its ok.) What is the molar mass of Pb(SO4)2? Explain how you calcu
kipiarov [429]

Answer:

399

Explanation:

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5 0
3 years ago
Read 2 more answers
How can one kg of iron melt more ice than 1 kg lead at 100 °C
Vanyuwa [196]

Answer:

Due to the specific heat capacity of iron, 0.444 J/(g·°C), is more than the specific heat capacity for lead, 0.160 J/(g·°C)

Explanation:

The given parameters are;

The metals provided to melt the ice and their temperature includes;

One kg (1000 g) of iron;

Specific heat capacity = 0.444 J/(g·°C)

Temperature = 100°C

1 kg (1000 g) of lead

Specific heat capacity = 0.160 J/(g·°C)

Temperature = 100°C

Therefore, the heat provided to the ice of mass m, and latent heat of 334 J/g at 0°C by the metals are as follows;

For iron, we have;

ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{iron} = Heat obtained from the iron by the ice

ΔQ_{iron} = 0.444 m × 1000 × (100 - 0) = 44400 J

Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

∴ Heat absorbed by the ice for melting, H_l = Mass of ice × Latent heat of ice

H_l = Mass of ice × 334 J/g = 44400 J

Mass of ice melted by the iron = 44400 J/334 (J/g) ≈ 132.9 g

Mass of ice melted by the iron ≈ 132.9 g

For lead, we have;

ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{lead} = Heat obtained from the iron by the ice

ΔQ_{lead} = 0.160 m × 1000 × (100 - 0) = 16000 J

Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

∴ Heat absorbed by the ice for melting, H_l = Mass of ice × Latent heat of ice

H_l = Mass of ice × 334 J/g = 16000 J

Mass of ice melted by the lead = 16000 J/334 (J/g) ≈ 47.9 g

Mass of ice melted by the lead ≈ 47.9 g

Therefore, mass of  ice melted by the iron, approximately 132.9 g, is more than mass of ice melted by the lead, approximately 47.9 g.

3 0
3 years ago
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