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3 years ago

How long do pop rocks fizz inside of a humans mouth?

Chemistry

1 answer:

Mumz [18]3 years ago

7 0

All matters how much u put in ur mouth if a lot about a min a little about 35 or a little more seconds

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How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

3 0

4 years ago

a sample of double-stranded dna contains 42% cytosine. approximately what percent of the nucleotides in this sample will be thym

Simora [160]

Answer:

8% thymine

Explanation:

7 0

3 years ago

Classify..use the periodic table to classify the elements potassium, bromine a d argon according to how likely their atoms lose

iren2701 [21]

Answer:

Classification will be Potassium, Bromine, and Argon

Explanation:

Potassium is more likely to lose electrons and form positive ion
Bromine actually gain electrons and forms negative ion
Argon does not lose or gain electrons

6 0

3 years ago

Plz, HELP ME!!!

Dafna1 [17]

Thermometer with black bulb because black reflects less heat than white

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3 years ago

Read 2 more answers

7g of gold is heated from 17 degrees C to 42 degrees C. How much energy (heat) was used? The specific heat capacity of gold is .

wel

Heat needed=mcθ
=7×0.031×(42-17)
=5.425cal

7 0

3 years ago