- Energy transformation includes ATP and ADP. at the point when energy is delivered, the response will in general separate a bigger particle to a more modest structure.
- For this situation, the bigger particle is ATP comprised of three phosphates bunches while ADP is just made out of two phosphate gatherings.
<h3>What is the energy source for the conversion of
ADP and ATP?</h3>
- The energy expected for the change of ADP into ATP is acquired from light during photosynthesis and from exothermic responses during cell breath in the two plants and creatures.
- ADP is produced on hydrolysis of ATP and the energy released in the process is utilised to carry out various cellular processes.
To learn more about energy release from the given link
brainly.com/question/1557907
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It is in period 3
It is in group 17
It is a chlorine atom because it has 17 electrons which means the atomic number is 17
The <span>simple machine found on the head of the ax is </span>Wedge. A wedge is an inclined plane that can be moved. When an ax is used
to split wood, the ax handle
exerts a force on the blade of
the axe, which is the wedge. That force pushes the wedge
down into the wood. The wedge in turn exerts an
output force splitting the wood in two.
Answer:
0.24 M
Explanation:
Molarity = Moles solute / Liters solution
Step 1: Identify variables
400 mL = Liters solution
0.60 moles = Moles solute
Step 2: Identify conversions
1 L = 1000 mL
Step 3: Convert mL to L
400mL(1 L/1000mL) = 0.4 L
Step 4: Find molarity
M = (0.4 L)(0.60 mol) = 0.24 M
Answer:
13.4 (w/w)% of CaCl₂ in the mixture
Explanation:
All the Cl⁻ that comes from CaCl₂ (Calcium chloride) will be precipitate in presence of AgNO₃ as AgCl.
To solve this problem we must find the moles of AgCl = Moles of Cl⁻. As 2 moles of Cl⁻ are in 1 mole of CaCl₂ we can find the moles of CaCl₂ and its mass in order to find mass percent of calcium chloride in the original mixture.
<em>Moles AgCl - Molar mass: 143.32g/mol -:</em>
0.535g * (1mol / 143.32g) = 3.733x10⁻³ moles AgCl = Moles Cl⁻
<em>Moles CaCl₂:</em>
3.733x10⁻³ moles Cl⁻ * (1mol CaCl₂ / 2mol Cl⁻) = 1.866x10⁻³ moles CaCl₂
<em>Mass CaCl₂ -Molar mass: 110.98g/mol-:</em>
1.866x10⁻³ moles CaCl₂ * (110.98g/mol) = 0.207g of CaCl₂ in the mixture
That means mass percent of CaCl₂ is:
0.207g CaCl₂ / 1.55g * 100 =
<h3>13.4 (w/w)% of CaCl₂ in the mixture</h3>
