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elena-s [515]
3 years ago
9

When the moon appears larger than 1/2 but less than full

Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
5 0
It is called a waxxing gibbous, pls brainliest
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Write your answer with correct significant figures (*no scientific notation): 847.3219 x 34.6 x 1.4560 =​
Lunna [17]

Answer:

42686.04375

Explanation:

847.3219*34.6=2317.33774 multiply this by the next number 1.4560 to get 42686.04375

3 0
3 years ago
How many grams of NaOH are<br> needed to make 400. mL of<br> 1.50 M solution?
juin [17]

Answer:

24g of NaOH are required

Explanation:

Molarity, M, is an unit of concentration widely used in chemistry defined as the ratio between moles of solute (In this case, NaOH), and volume of solution in liters.

We can find the moles of NaOH and its mass with the volume and desired concentration as follows:

<em>Moles NaOH:</em>

400.0mL = 0.400L * (1.50mol / L) = 0.600 moles NaOH

<em>Mass NaOH -Molar mass: 40.0g/mol-:</em>

0.600 moles * (40.0g / mol) =

<h3>24g of NaOH are required</h3>
7 0
3 years ago
Write at least three characteristics of acids and three characteristics of bases. These characteristics should be what makes the
ki77a [65]
Characteristics of acid

-It tastes sour
-It reacts with metals and carbonates
-It turns blue litmus paper red

Characteristics of base

-It tastes bitter
-It feels slippery
-It turns red litmus paper blue.
3 0
3 years ago
How many moles of nitrogen are contained in 18.65 L at STP?
stira [4]
1 mole of any gas under STP  ----- 22.4 L

18.65 L*1 mol/22.4 L ≈ 0.8326 mol N2
8 0
3 years ago
Read 2 more answers
Eading and
4vir4ik [10]

Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles

The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

Mass of Cl_2= moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g

Thus 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

5 0
2 years ago
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