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bazaltina [42]
3 years ago
13

Why does increasing the temperature of a reaction cause the reaction rate to increase?

Chemistry
2 answers:
Alina [70]3 years ago
8 0

The answer is (B).

As temperature increases, the number of high energy collisions increases. It is because of these collisions that a reaction will result.

marissa [1.9K]3 years ago
3 0

Answer:

The correct answer is "Increased energy enables more particles to collide."

Explanation:

The reaction rate is defined as the change in the concentration of one of the reagents or products, in a time interval in which the change takes place.

For a chemical reaction to take place, the molecules of the reagents must collide, and must also collide effectively. In other words, these shocks must be produced with sufficient energy so that they can break and form chemical bonds. In the crash there must be proper orientation.

When increasing the temperature, the molecules will possess greater kinetic energy, which is that energy related to the movement of the molecules. Consequently, these molecules will move faster.Thus, the possibility of colliding with another molecule increases significantly. In this way, the reaction rate increases.

So, <u><em>the correct answer is "Increased energy enables more particles to collide."</em></u>

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Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2.568%20%5Ctimes%205.8%7D%7B4.186%7D%20" id="TexFormula1" title=" \frac{2.568 \ti
melomori [17]
Using a calculator:

(2.568 x 5.8)/4.186 = 3.5581460…
= 3.56 (3sf)

You didn’t specify the correct number of significant figures needed.
3 0
3 years ago
If I have a 50.0 liter container that holds 45 moles of gas at a
Darina [25.2K]
V= 50. L n=45 mol T= 200°C = 473k P=?

CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)


P = 30am or 4000 kPa
5 0
4 years ago
Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the followi
Nitella [24]

Answer:

126.4 g of C_{4}H_{10} are required

Explanation:

Balanced reaction: 2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O

According to balanced reaction-

8 moles of CO_{2} are produced from 2 moles of C_{4}H_{10}

So, 8.70 moles of CO_{2} are produced from (\frac{2}{8}\times 8.70) moles of C_{4}H_{10} or 2.175 moles of C_{4}H_{10}

Molar mass of C_{4}H_{10} = 58.12 g/mol

So, mass of C_{4}H_{10} required = (2.175\times 58.12)g = 126.4 g

Hence 126.4 g of C_{4}H_{10} are required

5 0
3 years ago
Which element reacts spontaneously with 1.0M HCl (aq) at room temperature?
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8 0
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