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Rama09 [41]
3 years ago
12

a compound has a molar mass of 134.13 g/mol-1 and the percent composition is 44.77% carbon, 7.52% hydrogen and 47.71% oxygen. wh

at is the molecular formula?
Chemistry
1 answer:
wariber [46]3 years ago
5 0

Answer:

Molecular formula = C₅H₁₀O₄

Explanation:

Given data:

Percentage of hydrogen = 7.52%

Percentage of carbon = 44.77%

Percentage of oxygen = 47.71%

Molecular formula = ?

Solution:

Number of gram atoms of H = 7.52 / 1.01 = 7.445

Number of gram atoms of O = 47.71 / 16 = 2.982

Number of gram atoms of C = 44.77/ 12 = 3.731

Atomic ratio:

            C                      :      H                     :         O

           3.731/2.982      :     7.445/2.982    :       2.982/2.982

                1.25              :           2.5              :        1

C : H : O = 1.25 : 2.5 : 1

C : H : O = 4(1.25 : 2.5 : 1 )

Empirical formula is C₅H₁₀O₄

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 5×12 + 10×1.01 + 4×16 = 134.1

n = 134.13/ 134.1

n = 1

Molecular formula = n (empirical formula)

Molecular formula = 1 (C₅H₁₀O₄)

Molecular formula = C₅H₁₀O₄

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Zepler [3.9K]

Answer:

2,909 M

Explanation:

molair mass is of.ethylene is 26,04 g/mol

first you need to calculate how much mL 3 kg is. You can do this by using the density of ethylene: 1,1 g/mL.

3000 g x 1.1 = 3300 mL = 3,3 L

Next you need to calculate the amount of moles:

250 g / 26,04 g/mol = 9,60 mol

Now you can calculate the molarity:

9,6/3.3 = 2,909 M

I don't know the answer for the second question. I'm sorry.

3 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
Bond length is the distance between the centers of two bonded atoms. On the potential energy curve, the bond length is the inter
mariarad [96]

Answer:

152 pm

Explanation:

According to the question, we can estimate the bond length from the given values of the atomic radii. This now is the upper limit of the bond length for the molecule.

Since we have that;

Atomic radius of H= 37.0 pm

Atomic radius of Br = 115.0 pm

Bond length = Atomic radius of H + Atomic radius of Br

Bond length = 37.0 pm + 115.0 pm

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faltersainse [42]

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Explanation:

3 0
3 years ago
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