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3 years ago

What keeps a red giant from collapsing under its own

1 answer:

6 0

I'd say that because of gravity and the material made the red giant it's holding all the material together to be in one piece years and years to come.

Hope that helped! <3 ^-^

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How does a turbine produce energy

Ira Lisetskai [31]

A wind turbine turns wind energy into electricity using the aerodynamic force

5 0

3 years ago

A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the mountaintop to be θ when she

valentina_108 [34]

Let t = Theta and p = Phi
Tan t = y/x Then x =y/Tant.
Tant = y/(x-d) x-d = y/Tanp
y/Tant - d = y/Tanp
y -d*Tanr = y*Tant/Tanp
y-y*Tant/Tanp = d*Tanr
y(1 - Tanr/Tanp = d*Tant

y = d*Tant/(1-Tant/Tanp)

7 0

3 years ago

Compare the magnitude of the magnetic field at the center of a circular current loop of radius 30 mm with the magnitude of the m

NISA [10]

Answer:

Ratio of magnetic field will be $\frac{B}{B'}=0.0055$

Explanation:

We have given radius of the loop r = 30 mm = 0.03 m

We know that magnetic field at the center of the loop is given by

$B=\frac{\mu _0i}{2r}$ ---------eqn 1

Number of turns in the solenoid is given as n = 3 turn per mm = 3000 turn per meter

We know that magnetic field due to solenoid is given by

$B'=n\mu _0i$ -------------eqn 2

Now dividing eqn 1 by eqn 2

$\frac{B}{B'}=\frac{\frac{\mu _0i}{2r}}{\mu _0ni}=\frac{1}{2nr}=\frac{1}{2\times 3000\times 0.03}=0.0055$

4 0

3 years ago

TRUE OR FLASE

BaLLatris [955]

Answer:

true for first and false for second

Explanation:

5 0

2 years ago

A vertical spring stretches 3.4 cm when a 12-g object is hung from it. The object is replaced with a block of mass 26 g that osc

Mariulka [41]

Answer:

Period of motion is approximately 0.5447 seconds

Explanation:

We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)

F = k * x

0.012 kg * 9.8 m/s^2 = k 0.034 m

k = 0.012 kg * 9.8 m/s^2 / (0.034 m)

k = 3.46 N/m

now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

$T=2\pi\,\sqrt{\frac{m}{k} }$

which in our case becomes:

$T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec$

4 0

3 years ago