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lara31 [8.8K]
4 years ago
13

A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the mountaintop to be θ when she

is a horizontal distance x from the mountaintop. After walking a distance d closer to the mountain, she measures the angle of elevation of the mountaintop to be φ. Neglecting the height of the woman’s eyes above the ground, draw a well-labeled diagram representing this situation and find an expression for the height of the mountain, y, in terms of d, φ, and θ. Note that your expression cannot contain x.
Physics
1 answer:
valentina_108 [34]4 years ago
7 0
Let t = Theta and p = Phi
Tan t = y/x    Then x =y/Tant.
Tant = y/(x-d)  x-d = y/Tanp
y/Tant  - d = y/Tanp
y -d*Tanr = y*Tant/Tanp
y-y*Tant/Tanp  =  d*Tanr
y(1 - Tanr/Tanp = d*Tant

y = d*Tant/(1-Tant/Tanp)
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Answer:

The amount of solid ice remaining after 6 hours is approximately 3.68664 kg

Explanation:

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The temperature of the melting ice inside the box, T₂ = 0°C

The latent heat of fusion of ice, L_f = 3.35 × 10⁵ J/K/hr/kg

The surface area of the box, A = 6·s² 6 × (0.3 m)² = 0.54 m²

The coefficient of thermal conductivity, K = 0.01 J/s·m⁻¹·K⁻¹

For thermal equilibrium, we have;

The heat supplied by the surrounding = The heat gained by the ice

The  heat supplied by the surrounding, Q = K·A·ΔT·t/d

Where;

ΔT = T₁ - T₂ =  45° C - 0° C = 45° C

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Q = K·A·ΔT·t/d = 0.01 × 0.54 × 45 × 6× 60×60/0.05 = 104976

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The heat gained by the ice = L_f × m_{melted \ ice} =3.35 × 10⁵ J/kg × m_{melted \ ice}

Therefore, from Q =  L_f × m_{melted \ ice}, we have;

Q = 104976 J =  L_f × m_{melted \ ice} = 3.35 × 10⁵ J/kg × m_{melted \ ice}

104976 J = 3.35 × 10⁵ J/kg × m_{melted \ ice}

m_{melted \ ice} = 104976 J/(3.35 × 10⁵ J/kg) ≈ 0.31336 kg

The mass of melted ice, m_{melted \ ice} ≈ 0.31336 kg

∴ The amount of solid ice remaining after 6 hours, m_{ice} = m - m_{melted \ ice}

Which gives;

m_{ice} = m - m_{melted \ ice} = 4.0 kg - 0.31336 kg ≈ 3.68664 kg

The amount of solid ice remaining after 6 hours, m_{ice} ≈ 3.68664 kg.

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