Oooo that ones hard. ummm... idk i think we should just leave it to the experts ya know.
Answer:
the signs of heat and work are; -Q and -W
Explanation:
The first law of thermodynamics is given by; ΔU = Q − W
where;
ΔU is the change in internal energy of a system,
Q is the net heat transfer (the sum of all heat transfer into and out of the system)
W is the net work done (the sum of all work done on or by the system).
Now, The system in this case is the tire and since the air gets warmer, heat must have left the system. Therefore Q is negative (-Q).
Since work is done by the system, W remains negative.
Thus, the signs of heat and work are; -Q and - W
Answer:
Final vertical velocity = -29m/s
Horizontal distance = 100m
Height = 20.41m
Explanation:
1. The vertical final velocity can be calculated thus: vy = vyo - gt
Where;
vy = vertical velocity (m/s)
vyo = vertical initial velocity (20m/s)
g = acceleration due to gravity (9.8m/s²)
t = time (5s)
Hence, vy = vyo - gt
vy = 20 - (9.8 × 5)
vy = 20 - 49
vy = -29m/s
2. x = V0 x t
Where;
x = horizontal distance (m)
Vo = initial velocity
t = time (s)
x = 20 × 5
x = 100m
3. Maximum height = (voy)²/2g
= 20²/ 2 × 9.8
= 400/19.6
= 20.41m
Its larger and if u where wondering to positive ions are smaller
Answer:
31.2 m/s
Explanation:
= Frequency of approach = 480 Hz
= Frequency of going away = 400 Hz
= Speed of sound in air = 343 m/s
= Speed of truck
Frequency of approach is given as
eq-1
Frequency of moving awayy is given as
eq-2
Dividing eq-1 by eq-2
= 31.2 m/s
