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The probability that the red balls can be drawn before the green ball is drawn is 3/8.
<h3>What is Probability?</h3>
The probability is the measure of the likelihood of an event to happen.
Given:
red balls= 3
white balls = 4
green balls = 1
So, Probability of red balls
=3/8
Probability of green balls
=1/7
Learn more about probability here:
brainly.com/question/14546377
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Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
I got it as 4 when calculating all have the same number which is 133
