Answer:
- <em>The partial pressure of the oxygen gas is </em><u>96.00 KPa</u>
Explanation:
The law of partial pressures states that, in a mixture of gases, the total pressure of the mixture is equal to the sum of the individual pressures of each gas, as if each gas were alone in the mixture.
So:
- Total pressure = ∑ individual pressures
- Total pressure = Partial pressure of the water + Partial pressure of oxygen
- 98.67 KPa = 2.67 KPa + Partial pressure of oxygen
- Partial pressure of oxygen = 98.67 KPa - 2.67 KPa
- Partial pressure of oxygen = 96.00 KPa ← answer
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams
therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams
Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
Answer:
A
Explanation:
Hydrogen and chlorine need to be balanced. There is an equal amount of magnesium on each side
Answer:
The volume that the same gas will occupy at 101.3 kPa if the temperature is kept constant is 5.27 L.
Explanation:
As the volume increases, the particles (atoms or molecules) of the gas take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law that says:
"The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
P * V = k
Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1 * V1 = P2 * V2
In this case, you have:
- P1= 92 kPa
- V1= 5.80 L
- P2= 101.3 kPa
- V2= ?
Replacing:
92 kPa* 5.80 L= 101.3 kPa* V2
and solving, you get:

V2= 5.27 L
<u><em>The volume that the same gas will occupy at 101.3 kPa if the temperature is kept constant is 5.27 L.</em></u>