Standard entropy of the compounds of interest are as follows,

= 212.1 J/K.mol

= 205.0 J/K.mol

= 213.6 J/K.mol

= 69.9 J/K.mol
Now for the reaction:
<span>C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l)
</span>
ΔS°reaction = ∑

- ∑

∴ ΔS°reaction =( 6

+ 6

) - (

+ 6

= 205.0 J/K.mol)
∴ ΔS°reaction = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)]
∴ ΔS°reaction = 258.9 ≈ 262 J/ K mol.
Thus, correct answer is option C
Different forms of matter have different melting/boiling points. For example, at 100 degrees Celsius, H2O (water) will turn from lliquid to gas. But NaOH (table salt) doesn't even go from solid to liquid until some 800 degrees Celsius. So, in order to figure out which state matter is at 35 Celsius, you'd have to be more specific about what kind of matter...
167 mL
P1V1 = P2V2
P1 = .8 atm
V1 = 250 mL
P2 = 1.2 atm
Solve for V2 —> V2 = P1V1/P2
V2 = (0.8 atm)(250 mL) / (1.2 atm) = 167 mL