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4 years ago

Which development was a direct result of the

2 answers:

7 0

the development that became a direct result of thebaby boom that followed World War II would be: increase in suburbanization Baby boomers makes the urban city became a lot more crowded and often caused heavy traffic every single day. Because if this, many people decided to live in a suburban area while commuting to work in the city at the same time

Keith_Richards [23]4 years ago

6 0

Many countries experienced the baby boom after the World War II ended. The baby boom resulted to the increase in suburbanization which is number 2. The more people/babies born, the more houses are needed. The countries who experienced the baby boom were not large enough to cater the population so mass developments happened.

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What part of the microscope is the letter k?

snow_tiger [21]

Answer:

if you are asking k then the round one is condenser

if not then its a stage clip

6 0

3 years ago

You could add solid KCl to the solution to precipitate out AgCl(s). What mass of KCl is needed to precipitate the silver ions fr

padilas [110]

Answer:

0.143 g of KCl.

Explanation:

Equation of the reaction:

AgNO3(aq) + KCl(aq) --> AgCl(s) + KNO3(aq)

Molar concentration = mass/volume

= 0.16 * 0.012

= 0.00192 mol AgNO3.

By stoichiometry, 1 mole of AgNO3 reacts with 1 mole of KCl to form a precipitate.

Number of moles of KCl = 0.00192 mol.

Molar mass of KCl = 39 + 35.5

= 74.5 g/mol

Mass = molar mass * number of moles

= 74.5 * 0.00192

= 0.143 g of KCl.

4 0

4 years ago

One of relatively few reactions that takes place directly between two solids at room temperature is <img src="https://tex.z-dn.n

kolbaska11 [484]

Answer:

a) Ba(OH)₂.8H₂O(s) + 2 NH₄SCN(s) → Ba(SCN)₂(s) +10 H₂O(l) + 2 NH₃(g)

b) 3.14g must be added

Explanation:

a) For the reaction:

Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) + H₂O(l) + NH₃(g)

As you see, there are 8 moles of water in reactants and 2 moles of oxygen in octahydrate, thus, water moles must be 10:

Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) +10 H₂O(l) + NH₃(g)

To balance hydrogens, the other coefficients are:

Ba(OH)₂.8H₂O(s) + 2 NH₄SCN(s) → Ba(SCN)₂(s) +10 H₂O(l) + 2 NH₃(g)

b) As you see in the balanced reaction, 1 mole of barium hydroxide octahydrate reacts with 2 moles of NH₄SCN. 6.5g of Ba(OH)₂.8H₂O are:

6.5 g × (1mol / 315.48g) = 0.0206moles of Ba(OH)₂.8H₂O. Thus, moles of NH₄SCN that must be used for a complete reaction are:

0.0206moles of Ba(OH)₂.8H₂O × ( 2 mol NH₄SCN / 1 mol Ba(OH)₂.8H₂O) = 0.0412moles of NH₄SCN. In grams:

0.0412moles of NH₄SCN × ( 76.12g / 1mol) = 3.14g must be added

8 0

4 years ago

Read 2 more answers

If you were able to magnify a penny down to the atomic level, what two

Lena [83]

The two observations you would make about the atoms are

They are made up largely of empty space
Their mass is concentrated at the center called a nucleus

These observations were made by Ernest Rutherford in his model of the atom established in 1911, when he performed his gold foil experiment and observed the scattering angle of the alpha particles which led him to conclude that the mass of the atom was concentrated at the center.

Also, that most of the alpha particles also went through the gold foil suggested that the atom was made up basically of empty space.

So,

The two observations you would make about the atoms are

They are made up largely of empty space
Their mass is concentrated at the center called a nucleus

Learn more about the atom here:

brainly.com/question/24873449

7 0

3 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago