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Travka [436]
3 years ago
15

7. Given the balanced equation:

Chemistry
1 answer:
Vika [28.1K]3 years ago
4 0
Gas molecules have more freedom in motion—and gases can be thought of as more “disordered”—than molecules of a solid, which are rigidly held in place. When it comes to phases, the entropy increases as you go from a solid to liquid to gas (the gaseous state having the greatest entropy and the solid state having the least).

So, as a sample of solid iodine sublimes to form gaseous iodine, the entropy of the sample increases.
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Which formula can be used to calculate the theoretical yield?
Bas_tet [7]

Answer:

Option C, (Actual yield ÷ percent yield) × 100

Explanation:

Theoretical yield is defined as the total amount of product formed for given reactants in a chemical reaction.  It is an ideal case which assumes no exceptions or wastage.

The mathematical relation between the actual yield, percent yield and theoretical yield is as follows -

P.Y. = \frac{M_{A.Y.}}{M_{T.Y.}} * 100

Where

P.Y. represents the percent yield a

M A.Y. represents the mass obtained from actual yield

M T.Y. represents the mass obtained from theoretical yield

Hence, if we rearrange the formula, we get -

M_{T.Y.} = \frac{M_{A.Y.}}{P.Y.} * 100

Hence, option C is correct

5 0
3 years ago
A sample of gold has a mass of 67.2 g and a volume of 3.5 cm3. the density of gold is
scoray [572]
67.2g/3.5cm3= 19.2g/cm3
6 0
3 years ago
Help this is my test
miss Akunina [59]

Answer:

the answer is v and z. you can see the pic

7 0
3 years ago
Read 2 more answers
La precipitación ácida es un agente de?
serg [7]

Answer:

acid precipitation is an agent of

Explanation:

4 0
4 years ago
La formula quimica de la molecula de agua H20 , si H = 1 gramos y O = 16 gramos . Cual es su composicion porcentual ? 88,88 % de
vesna_86 [32]

Answer:

88,88 % de O y 11,11 % de H

Explanation:

La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:

<em>Masa molar agua:</em>

2H = 2*1g/mol = 2g/mol

1O = 1*16g/mol = 16g/mol

Masa molar = 2 + 16 = 18g/mol

100g H2O * (1mol / 18g) = 5.556 moles H2O.

Moles de hidrógeno:

5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H

Moles Oxígeno = Moles H2O = 5.556 moles

La masa de hidrógeno es:

11.11mol * (1g/mol) 11.11g H

La masa de oxígeno es:

5.556 mol * (16g / 1mol) = 88.89g O

Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:

<h3>88,88 % de O y 11,11 % de H</h3>
7 0
3 years ago
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