7. Given the balanced equation:

1 answer:

4 0

Gas molecules have more freedom in motion—and gases can be thought of as more “disordered”—than molecules of a solid, which are rigidly held in place. When it comes to phases, the entropy increases as you go from a solid to liquid to gas (the gaseous state having the greatest entropy and the solid state having the least).

So, as a sample of solid iodine sublimes to form gaseous iodine, the entropy of the sample increases.

You might be interested in

Which element are in the compound CoCI2? Choose all correct answers.

Kobotan [32]

Answer:

the answer is cobalt and chloride

7 0

2 years ago

Read 2 more answers

Which of the following forms a new substance? melting, evaporating, freezing or burning

Slav-nsk [51]

It would be burning be cause when you freeze, evaporate, or melt anything it is just changing how fast the atoms are moving . Think of it like water, ice, and steam, they are all the same thing but in different forms because of melting, evaporating,and melting. Burning is breaking it down.

4 0

3 years ago

Read 2 more answers

How do many types of cells, like bacteria, reproduce?

umka2103 [35]

Answer:

cells like bacteria are bisexual so they split and their offspring is 100 percent like the parent and this process happens over and over

Explanation:

8 0

2 years ago

Which outcome is the main function of the light-dependent reactions of photosynthesis?

andrew-mc [135]

Answer:

oxygen, water and sugar are the out come of photosynthesis

7 0

3 years ago

A 29.7 g sample of iron ore is treated as follows. The iron in the sample is all converted by a series of chemical reactions to

Softa [21]

Answer: The mass of iron in the ore is 10.9 g

Explanation:

We are given:

Mass of iron (III) oxide = 15.6 g

We know that:

Molar mass of Iron (III) oxide = 159.69 g/mol

Molar mass of iron atom = 55.85 g/mol

As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.

To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:

In 159.69 g of iron (III) oxide, mass of iron present is $(2\times 55.85)=111.7g$

So, in 15.6 g of iron (III) oxide, mass of iron present will be = $\frac{111.7g}{159.69g}\times 15.6g=10.9g$

Hence, the mass of iron in the ore is 10.9 g

7 0

3 years ago