Answer:
173.83 mmHg is the vapor pressure of a ethylene glycol solution.
Explanation:
Vapor pressure of water at 65 °C=
Vapor pressure of the solution at 65 °C= 
The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.
Mass of ethylene glycol = 22.37 g
Mass of water in a solution = 82.21 g
Moles of water=
Moles of ethylene glycol=
173.83 mmHg is the vapor pressure of a ethylene glycol solution.
Answer:
3.33 L
Explanation:
We can solve this problem by using the equation:
Where the subscript 1 refers to one solution and subscript 2 to the another solution, meaning that in this case:
We input the data:
- 0.25 M * 100 L = 7.5 M * V₂
Thus the answer is 3.33 liters.
Answer:
3.01 × 10^24 particles
Explanation:
According to Avagadro, in one mole of a substance, there are 6.02 × 10^23 atoms or particles.
Using the formula: N = n × NA
Where;
N= number of particles or atoms
n = number of moles
NA = Avagadro's constant or number
This means that for 5 moles of a substance, there will be:
5 × 6.02 × 10^23
= 30.1 × 10^23
= 3.01 × 10^24 particles
