<u>Answer:</u> The volume of hydrogen gas formed is 9.5 L
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of aluminium = 7.01 g
Molar mass of aluminium = 27 g/mol
Putting values in above equation, we get:
The given chemical equation follow:
As, NaOH is present in excess. It is known as excess reagent.
So, aluminium is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of aluminium produces 3 moles of hydrogen gas.
So, 0.26 moles of aluminium will produce = of hydrogen gas
- The equation given by ideal gas follows:
where,
P = pressure of hydrogen gas = 1.00 atm
V = Volume of hydrogen gas = ? L
T = Temperature of hydrogen gas =
R = Gas constant =
n = number of moles of hydrogen gas = 0.39 moles
Putting values in above equation, we get:
Hence, the volume of hydrogen gas formed is 9.5 L