The teacher would need 40 centimeters of tape to hang 10 student projects.
Step-by-step explanation:
Given,
Tape used to hang projects = 36 centimeters
Number of projects hanged = 9
We will find unit rate;
9 projects = 36 centimeters
1 project = 
1 project = 4 centimeters
Therefore,
Tape needed to hang 10 projects = 4*10 = 40 centimeters
The teacher would need 40 centimeters of tape to hang 10 student projects.
Keywords: unit rate, multiplication
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First we would need to make a diagram, and from the given it would seem like it is a right triangle with the height as 760 ft. We have an angle given 89°18' which would need to be converted to degrees form, which is 89.3<span>°.
Now we would need to look for the ground distance, meaning the adjacent of the triangle. Since we have been given the angle and the height (which is the opposite side from the angle) we use the trigonometric function cotangent.
</span><span>760 Cot <span>[<span><span>(<span>89.3</span>)</span>∘</span>]</span>= 9.29 ft, that is the answer.</span>
So, first you must find the remaining angle measure. To do this add 25 and 90 then subtract from 180. The remaining angle measure is 65 degrees.
Next, use tangent, cosine, or sine to find the remaining side lengths.
I used sine of 25 which is opposite of hypo. which is sine 25 = y/43.
Multiply both side by 43 and you get y=18.17
Do the same to find x, but use the sine of 65, and you get sine 65 = x/43.
Multiply both sides by 43 and you get x=38.97
Hope this helped!
An exponential equation can be written from its description using the form
... y = (reference value)·((later value)/(reference value))^((t - (reference time))/(later time - reference time))
Here, we have
... reference value = 220; reference time = 2; later value = 880; later time = 4
so we can write the exponential equation as
... y = 220·(880/220)^((t-2)/(4-2)) = 220·4^(t/2 -1) = 55·2^t
Then for t=10, the expected number is
... y = 55·2^10 = 56,320
Answer:
low or moderate maybe I think
