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4 years ago

BRAINLIEST AND 25 POINTS!!! PLZ HELP!

Physics

2 answers:

madreJ [45]4 years ago

8 0

Boron is a metalloid, while neon is a noble gas.

Veseljchak [2.6K]4 years ago

5 0

I KNOW THE ANSWERRRR!
Boron is a metalloid, while neon is a noble gas!

Hope it helps frandd!

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Most of the mass of the milky way exists in the form of.

Andrews [41]

Answer: Dark matter.

Explanation: Hope it helps :)

7 0

3 years ago

Read 2 more answers

Find the wavelength of the balmer series spectral line corresponding to n = 15.

Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

= 1.097 × 10⁷ m⁻¹(1/4 -1/225)

= 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

= 1.097 × 10⁷ m⁻¹ 0.245556

= 2.693 10⁶ m⁻¹

So,

λ = 1/2.693 10⁶ m⁻¹

= 0.3712 10⁻⁶ m

= 371.2 mm

7 0

3 years ago

Parallel rays from a distant object are traveling in air and then are incident on the concave end of a glass rod with a radius o

skad [1K]

Answer:

the distance of image from the vertex is 45 cm and the image formed is in the glass.

Explanation:

distance of object, u = - infinity

radius of curvature, R = - 15 cm

refractive index, n = 1.5

Let the distance of image is v.

Use the formula

$-\frac{n1}{u}+\frac{n2}{v}=\frac{n2- n1}{R}\\\\-\frac{1}{\infty }+\frac{1.5}{v}=\frac{1.5-1}{-15}\\\\v=45 cm$

The image is in the glass.

8 0

3 years ago

A planet has two small satellites in circular orbits around the planet. the first satellite has a period 18.0 hours and an orbit

puteri [66]

The two satellites orbit around the same planet, so we can use Kepler's third law, which states that the ratio between the cube of the radius of the orbit and the orbital period is constant for the two satellites:
$\frac{r_1^3}{T_1^2}= \frac{r_2^3}{T_2^2}$
where
$r_1$ is the orbital radius of the first satellite
$r_2$ is the orbital radius of the second satellite
$T_1$ is the orbital period of the first satellite
$T_2$ is the orbital period of the second satellite

If we use the data of the problem and we re-arrange the equation, we can calculate the orbital period of the second satellite:
$T_2 = \sqrt{T_1^2 ( \frac{r_2}{r_1} )^3} = \sqrt{(18.0 h)^2 ( \frac{3\cdot 10^7 m}{2 \cdot 10^7 m} )^3} = 33.1 h$

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3 years ago

The different odds of survival between a preterm and a full-term newborn involve: cephalic development.

DENIUS [597]

Answer: B

Explanation:

5 0

3 years ago