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4 years ago

Giant cave systems have formed through the reaction of acids with the that make up limestone.

Physics

2 answers:

omeli [17]4 years ago

6 0

Answer:

C carbonates

Explanation:

Took the test on edgunity

seraphim [82]4 years ago

3 0

The answer is C. Carbonates

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Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:

lukranit [14]

Answer:

B. Quantum Mechanics

Explanation:

Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.

4 0

3 years ago

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A toy car's movements is measured using photogates.

Cloud [144]

Answer:

a) the velocity increases then decreases.

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4 years ago

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Consider a disk of radius 2.6 cm with a uni- formly distributed charge of +6.7.1C. Compute the magnitude of the electric field a

MrRissso [65]

Answer:

E=15.3*10¹³ N/C : approximate

Explanation:

We use the following formula to calculate the electric field due to a disk with uniform surface charge at a point P that is along the central perpendicular axis of the disk and at a distance x from the center of the disk:

E= 2*π*k*σ*F Fórmula ( 1 )

$F= 1-\frac{x}{\sqrt{R^{2}+x^{2} } }$

E: Electric field at point P (N/C)

σ: surface charge density (C/m²)

R: disk radio (m)

x :distance from the center of the disk to the point P located on the axis of the disk (m)

K: Coulomb constant ( N*m²/C)

Equivalences

1cm = 10⁻²m

1mm = 10⁻³m

Data

R =2.6 cm= 2.6*10⁻²m = 0.026m

x=3.7 mm = 3.7* 10⁻³m = 0,0037 m

Q=+6.71C.

k= 8.98774 * 10⁹ N* m²/C

Calculation of surface charge density (σ )

σ= Q/A

Q: uniformly distributed charge (C)

A: disk area (m²) = π*R²

σ= +6.71C/π*(2.6*10⁻²)²m² = 3159.56C/m²

Calculation of the electric field at point P

We apply formula (1) and replace data

E= 2*π*3159.56*8.98774*10⁹ *F

$F= 1-\frac{x}{\sqrt{R^{2}+x^{2} } }$

E=15.3*10¹³ N/C : approximate

3 0

3 years ago

PLZ HELP ME!!!!!!!!

mote1985 [20]

Answer:

1. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.77955 m

now frequency is given by

$f = \frac{343m/s}{ 0.77955m}$

f = 440 Hz

2. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.52028 m

now frequency is given by

$f = \frac{343m/s}{ 0.52028m}$

f = 659.3 Hz

3. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.65552 m

now frequency is given by

$f = \frac{343m/s}{ 0.65552m}$

f = 523.25 Hz

4. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 587.33 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{587.33}$

$\lambda = 0.584 m$

5. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 493.88 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{493.88}$

$\lambda = 0.6945 m$

6. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 698.46 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{698.46}$

$\lambda = 0.491 m$

7. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.5840 m

now frequency is given by

$f = \frac{343m/s}{0.5840m}$

f = 587.3 Hz

8. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.4375 m

now frequency is given by

$f = \frac{343m/s}{0.4375m}$

f = 784 Hz

9. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 783.99 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{783.99}$

$\lambda = 0.4375 m$

10. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 659.26 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{659.26}$

$\lambda = 0.520 m$

4 0

3 years ago

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When light reaches a barrier or the edge of an opening it diffracts, which means that the light _________.

Reptile [31]

Diffraction is the slight bending of light when it passes around the edge of an object. The amount of bending depends on the relative of the wavelength of the light wave to the size of the opening. If the opening is much larger than the wavelength the bending will be almost unnoticeable but if the two are equal or closer in length then the diffraction will be noted. Therefore, the correct answer is bends.

3 0

3 years ago

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