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3 years ago

100 points

Physics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

10.21m/s²

Explanation:

Radial acceleration, also known as centripetal acceleration, refers to the acceleration of an object along the circular radius. It can be calculated using the formula:

a(r) = v²/r

Where a(r) = radial acceleration

v = velocity

r = radius of the circular path

According to the information provided in the question, velocity (v) = 17.5m/s, radius = 30m. Hence;

a(r) = v²/r

a(r) = 17.5²/30

a(r) = 10.208333

a(r) = 10.21m/s²

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a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum

7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 × $10^{-2}$ m

height (h) =8.8 cm = 8.8 × $10^{-2}$ m

total charge (q) =6.1× $10^{-7}$ C

To solve:

volume charge density (ρ)

We know;

volume of cylinder = π ×r × r × h

volume of cylinder =3.14 × 2.1 × 2.1 × $10^{-4}$ × 8.8 × $10^{-2}$

volume of cylinder (v) = 122.23 × $10^{-6}$

ρ = 6.1× $10^{-7}$ ÷ 122.23 × $10^{-6}$

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

3 0

3 years ago

Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of

natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00 m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

$r'=\sqrt{d^2+r^2}$

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

$r'=\sqrt{(1.00)^2+(4.00)^2}$

$r'=\sqrt{1.00+16.00}$

$r'=4.12\ m$

We need to calculate the path difference

Using formula of path difference

$|r'-r|=4.12-4.00$

$|r'-r|=0.12\ m$

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

Where, v = speed of sound

f = frequency

Put the value into the formula

$\lambda=\dfrac{343}{300}$

$\lambda=1.143\ m$

We need to calculate the phase difference

Using formula of phase difference

$\phi=\dfrac{2\pi\times|r'-r| }{\lambda}$

$\phi=\dfrac{2\pi\times0.12}{1.143}$

$\phi=0.659\ rad$

Hence, The phase difference is 0.659 rad.

7 0

3 years ago

Which telescopes must be placed in orbit around earth in order to observe short-wavelength radiation?.

son4ous [18]

Space telescopes must be placed in orbit around earth in order to observe short-wavelength radiation.

<h3>What is telescope?</h3>

A telescope is an optical instrument that uses lenses, curved mirrors, or a combination of both to watch distant objects.

When atoms in a gas reach this temperature, they travel so quickly that when they collide, they release X-ray photons with wavelengths smaller than 10 nanometers.

Because the Earth's atmosphere prevents all X-rays from space, these wavelengths must be seen using space telescopes.

To study short-wavelength radiation, space telescopes must be put in orbit around the Earth.

Hence, space telescope is the correct answer.

To learn more about the telescope, refer:

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6 0

2 years ago

6. A student notices that when a weight is hung on a spring, the spring stretches. She decides conduct an experiment to determin

natima [27]

Answer:

Explanation:

She says that the object of the experiment is to see how far the string stretches given a mass attached to the string.

The only thing that is at issue is either the mass or the amount the string stretches.

Nothing else matters.

The dependent variable therefore is the amount the string stretches. So the last choice is the answer.

4 0

3 years ago

PLEASE HELP AND I WILL GIVE BRAINLIEST

san4es73 [151]

Answer:

A: Sound waves produce an echo

Explanation:

because the cup is a hard smooth surface you can hear the voice

3 0

3 years ago

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