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Shkiper50 [21]
3 years ago
8

A package of chips weighs 45 grams. How much is that in kilograms?

Physics
2 answers:
stealth61 [152]3 years ago
7 0
0.045 kilograms that's the answer conversion is always so easy because you can always look it up
nirvana33 [79]3 years ago
5 0
45 grams is 0.045 kilograms
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Which gaseous giants did renaissance scientists such as galileo know about? select two options. jupiter mars neptune saturn uran
maksim [4K]

Answer:

Jupiter and Saturn

Please Mark Brainliest If This Helped!

5 0
3 years ago
A particle whose speed is 50 m/s moves along the line from A(2,1) to B(9,25). Find its velocity vector in the form of ai +bj.
Kitty [74]

To write it in the form ai + bj, we need to find a and b which are:

a = x component

b = y component

 

length of x = 9 – 2 = 7

length of y = 25 – 1 = 24

 

tan θ = 24 / 7

θ = 73.74°

 

a = (50 m/s) cos 73.74

a = 14 m/s

 

b = (50 m/s) sin 73.74

b = 48 m/s

 

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14i + 48j

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3 years ago
What stands for sound navigation and ranging
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6 0
4 years ago
You have a mass of 55kg and are riding your frictionless skateboard, which has a mass of 5kg, in a straight line at a speed of 4
Rzqust [24]

Given

m1(mass of the first object): 55 Kg

m2 (mass of the second object): 55 Kg

v1 (velocity of the first object): 4.5 m/s

v2 (velocity of the second object): ?

m3(mass of the object dropped): 2.5 Kg

The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:

Pa= Pb

Where Pa is the momentum before collision and Pb is the momentum after collision.

Now applying this law for the above problem we get

Momentum before collision= momentum after collision.

Momentum before collision = (m1+m2) x v1 =(55+5)x 4.5 = 270 Kgm/s

Momentum after collision = (m1+m2+m3) x v2 =(55+5+2.5) x v2

Now we know that Momentum before collision= momentum after collision.

Hence we get

270 = 62.5 v2

v2 = 4.32 m/s




7 0
3 years ago
Galaxy evolution is a very active area of research. Look for information on a future observatory/mission that will investigate g
Maslowich

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4 years ago
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