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brilliants [131]
3 years ago
7

The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil

l balance the chemical equation.
()Fe + ()O2 → ()Fe2O3

Physics
2 answers:
attashe74 [19]3 years ago
7 0

Answer:

here is the answer

Explanation:

have a good day

Brrunno [24]3 years ago
3 0

Answer:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

Explanation:

The original equation is:

Fe + O_2 \rightarrow Fe_2 O_3

We notice that:

- we have 1 atom of Fe on the left, and 2 atoms of Fe on the right

- we have 2 atoms of O on the left, and 3 atoms of O on the right

Therefore, the equation is not balanced.

In order to balance it, we can add:

- a coefficient 3 in front of O_2

- a coefficient 2 in front of Fe_2 O_3

So we have:

Fe + 3 O_2 \rightarrow 2Fe_2O_3

Now the oxygen is balanced, but the iron it not balanced yet, since we have 1 Fe on the left and 4 on the right. Therefore, we should add a coefficient 4 on the Fe on the left:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

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A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the
Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.  

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

-F_{f} + F = 0      

-F_{f} + ma = 0      

\mu mg = ma

\mu = \frac{a}{g}

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

v_{f}^{2} = v_{0}^{2} + 2ad

a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}

Where:  

d: is the distance traveled = 46.1 m

v_{f}: is the final speed of the truck = 0 (it stops)      

v_{0}: is the initial speed of the truck = 17.9 m/s

a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}        

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.  

\mu = \frac{a}{g}  

\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}

\mu = 0.35

Therefore, the minimum coefficient of friction required is 0.35.  

I hope it helps you!

4 0
3 years ago
R,=4.00 R, = 1000.00
lisabon 2012 [21]

Answer:1000.00

Explanation:

6 0
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Two protons move at speed v, one along the x axis and one along the y axis. What is the relative speed of the two protons? Evalu
forsale [732]

Answer:

0.85 c

Explanation:

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Relative velocity of the two protons is  given as

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If v = 3/5 c , then the relative speed = \sqrt{2} (3/5c) =0.85 c

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