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brilliants [131]
3 years ago
7

The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil

l balance the chemical equation.
()Fe + ()O2 → ()Fe2O3

Physics
2 answers:
attashe74 [19]3 years ago
7 0

Answer:

here is the answer

Explanation:

have a good day

Brrunno [24]3 years ago
3 0

Answer:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

Explanation:

The original equation is:

Fe + O_2 \rightarrow Fe_2 O_3

We notice that:

- we have 1 atom of Fe on the left, and 2 atoms of Fe on the right

- we have 2 atoms of O on the left, and 3 atoms of O on the right

Therefore, the equation is not balanced.

In order to balance it, we can add:

- a coefficient 3 in front of O_2

- a coefficient 2 in front of Fe_2 O_3

So we have:

Fe + 3 O_2 \rightarrow 2Fe_2O_3

Now the oxygen is balanced, but the iron it not balanced yet, since we have 1 Fe on the left and 4 on the right. Therefore, we should add a coefficient 4 on the Fe on the left:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

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A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista
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Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

C=\frac{\epsilon_0 A}{d}

where

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A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

C' = \frac{1}{2}C

The potential difference across the capacitor is given by

V= \frac{Q}{C}

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V' = 2 V

Now we can analyze the electric field between the plates of the capacitor, which is given by

E=\frac{V}{d}

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

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