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brilliants [131]
2 years ago
7

The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil

l balance the chemical equation.
()Fe + ()O2 → ()Fe2O3

Physics
2 answers:
attashe74 [19]2 years ago
7 0

Answer:

here is the answer

Explanation:

have a good day

Brrunno [24]2 years ago
3 0

Answer:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

Explanation:

The original equation is:

Fe + O_2 \rightarrow Fe_2 O_3

We notice that:

- we have 1 atom of Fe on the left, and 2 atoms of Fe on the right

- we have 2 atoms of O on the left, and 3 atoms of O on the right

Therefore, the equation is not balanced.

In order to balance it, we can add:

- a coefficient 3 in front of O_2

- a coefficient 2 in front of Fe_2 O_3

So we have:

Fe + 3 O_2 \rightarrow 2Fe_2O_3

Now the oxygen is balanced, but the iron it not balanced yet, since we have 1 Fe on the left and 4 on the right. Therefore, we should add a coefficient 4 on the Fe on the left:

4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3

You might be interested in
Captain Jack Sparrow has been marooned on an island in the Atlantic by his crew, and decides to builda raft to escape. The wind
Marianna [84]

Answer:

    d₃ = 37,729 km,     θ=  5.1º North of West

Explanation:

This is a velocity addition problem, the easiest way to solve it is to decompose the velocities in a Cartesian system, the x-axis coincides with the West-East direction and the y-axis with the South-North direction

* first displacement is

           d₁ₓ = 11 km

* second offset is

          cos 6 = d₂ₓ / d₂

          sin 6 = d_{2y} / d₂

          d₂ₓ = d₂ cos 6

          d_{2y} = d₂ sin 6

          d₂ₓ = 6 cos 6 = 5.967 km

          d_{2y} = 6 sin 6 = 0.6272 km

* third displacement is unknown

* fourth and last displacement

          cos (-11) = d₄ₓ / d₄

          sin (-11) = d_{4y} / d₄

          d₄ₓ = d₄ cos (-11)

          d_{4y} = d₄ sin (-11)

          d₄ₓ = 21 cos (-11) = 20.61 km

          d_{4y} = 21 sin (-11) = -4.007 km

They tell us that at the end of the tour you are back on the island, so the displacement must be zero

X axis

           x = d₁ₓ + d₂ₓ + d₃ₓ + d₄ₓ

           0 = 11 +5.967 + d₃ₓ + 20.61

           d₃ₓ = -11 - 5.967 - 20.61

           d₃ₓ = -37.577 km

Y axis  

          y = d_{1y} + d_{2y} + d_{3y} + d_{4y}

          0 = 0 + 0.6272 + d_{3y} -4.007

          d_{3y} = 4.007 - 0.6272

          d_{3y} = 3.3798 km

This distance can be given in the form of module and angle

Let's use the Pythagorean theorem for the module

           d₃ = \sqrt{d_{3x}^2 + d_{3y}^2}

           d₃ = \sqrt{37.577^2 + 3.3798^2}

           d₃ = 37,729 km

Let's use trigonometry for the angle

            tan θ = d_{3y} / d₃ₓ

            θ = tan⁻¹ \frac{d_{3y}}{d_{3x}}

            θ = tan-1 (-3.3798 / 37.577)

            θ = 5.1º

Since the y coordinate is positive and the x coordinate is negative, this angle is in the second quadrant, so the direction given in the form of cardinal coordinates is

            θ=  5.1º North of West

3 0
2 years ago
What cosmic accident is believed to form many irregularly shaped galaxies?
daser333 [38]
The kind of cosmic accident which is believed to form many irregular shaped galaxies is known as Galactic Collisions. Galactic Collisions are cosmic accidents that create irregularly shaped galaxies. The Andromeda-Milky Way Collision is one example of galactic collision that is predicted to occur in the next four (4) billion years, where the Andromeda and the Milky Way galaxy collide will collide with each other to form a new galaxy.
6 0
2 years ago
Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
Crank

Answer:

Fnet = 12 N

Explanation:

Force on a point charge due to another point charge = kq1q2 / d^2

Force on +32uC = due to + 20uC + due to -60uC

where uC = 1 x 10^-6 C and k = 9 x 10^9 N m^2 / C^2

Net Force =

= \frac{1}{4\pi \epsilon _0} [\frac{32 \times 10^-^6 \times60\times10^-^6}{(60/100)^2}-\frac{32 \times 10^-^6 \times20\times10^-^6}{ (40/100)^2}  ]

F_{net}=9 \times10^9\times 10^-^1^2[\frac{32\times60\times10^4}{60\times60} -\frac{32\times20\times10^4}{40\times40} ]

=90[32(\frac{80-60}{60\times 80} )]\\\\=90\times32\times0.004167\\\\=12N

Fnet = 12 N

8 0
3 years ago
A spacecraft left Earth to collect soil samples from Mars. Which statement is true about the strength of Earth’s gravity on the
Elina [12.6K]
The spacecraft increases
5 0
3 years ago
I NEED HELP ON THIS QUESTION!
GarryVolchara [31]

Forward because things that are in motion stay in motion.

Hope that helped!

~Izzy

4 0
2 years ago
Read 2 more answers
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