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Masja [62]
3 years ago
15

A bat is used to exert an impulse on a baseball. The mass of the bat is 2 kg and the mass of the ball is 0.25 kg. Compared to th

e impulse exerted by the bat on the ball, the impulse exerted by the ball on the bat is ___________.
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
The impulse exerted by the ball on the bat is THE SAME
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Calculate the total resistance in a parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω. (Hint: When converting to a decim
natta225 [31]

Answer:

Total resistance = 0.92Ω

Explanation:

For parallel connected resistors we have effective resistance

                 \frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+.....

Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.

That is

             R₁ = 2Ω

             R₂ = 3Ω

             R₃ = 4Ω

Substituting

             \frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eff}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\frac{1}{R_{eff}}=\frac{6+4+3}{12}\\\\R_{eff}=\frac{12}{13}=0.92ohm

Total resistance = 0.92Ω

6 0
3 years ago
An airplane is accelerating forward due to a force of 3320 newtons acting
Darya [45]

Two opposite forces generate a force whose magnitude is the difference of the two magnitudes, and whose direction is the same of the strongest one.

We have 3320 newtons forward, and 550 backwards.

So, the net force is forward, and has magnitude 3320-550=2770

5 0
3 years ago
A) a 70 kg runner begins his slide into third base moving at a speed of 4 m/s. How much work does friction do to slow him down a
egoroff_w [7]

Answer: I don’t know the answer to this but just do what i do look up the question I’m sure someone has answered this hope it helps❤️

Explanation:

5 0
2 years ago
5) A person holds a 1.7 kg bucket and lets it move down at
Elena L [17]

Answer:

12.5J

Explanation:

Given parameters:

Mass of bucket  = 1.7kg

Height  = 75cm  = 0.75m

Unknown;

Work done on the bucket by the person  = ?

Solution:

To solve this problem, we use the work done equation;

  Work done  = force x distance  = mgh

 m is the mass  

  g is the acceleration due to gravity

  h is the height

Now, insert parameters and solve ;

     Work done  = 1.7 x 9.8 x 0.75  = 12.5J

7 0
2 years ago
A veritical brass rod of circular section is loaded by placing a 10 kg wt on top of it .if it's length is 1 m. it's radius of cr
Inga [223]

Answer:

4.37 * 10^-4 J

Explanation:

Energy stored :

mgΔl / 2

m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m

Δl = mgl / πr²Y

Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m

Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10

Δl = 98 / 3.5 * π * 10^6

Δl = 0.00000891267

Energy stored :

mgΔl / 2

(10 * 9.8 * 0.00000891267) / 2

= 0.00043672083 J

4.37 * 10^-4 J

3 0
2 years ago
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