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sergey [27]
3 years ago
5

Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?

Physics
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

6 m/sec

Explanation:

12/2=6

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A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
ludmilkaskok [199]

Answer : Height, h = 20.4 m

Explanation :

It is given that,

Mass of an object, m = 500 g = 0.5 kg

Gravitational potential energy, PE = 100 J

The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :

PE = m g h

where,

h is the height of the cliff.

100\ J=0.5\ kg\times 9.8\ m/s^2\times h

h = 20.40 m

So, the height of the cliff is 20.4 m.

7 0
3 years ago
How has globalization led to underdeveloped countries?
Readme [11.4K]

Answer: Economic growth is the main channel. Globalization can affect poverty. when countries open up to trade, they tend to grow faster and living standards do tend to increase.

Explanation: I hope this helps :)

5 0
2 years ago
Multiple-Concept Example 6 reviews the concepts that play a role in this problem. A diver springs upward with an initial speed o
adell [148]

Answer:

Part a)

v_f = 7.99 m/s

Part b)

y = 3.25 m

Explanation:

Part a)

Since the diver is moving under gravity

so here its acceleration due to gravity will be uniform throughout the motion

so here we will have

v_f^2 - v_i^2 = 2 a y

here we have

v_i = 2.22 m/s

y = -3 m

v_f^2 - (2.22)^2 = 2(-9.81)(-3)

v_f = 7.99 m/s

Part b)

at highest point of his motion the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a (\Delta y)

0 - 2.22^2 = 2(-9.81)(y - 3)

y = 3.25 m

7 0
3 years ago
Which is the force that slows moving things down?
BlackZzzverrR [31]

i think centripetal Force

7 0
3 years ago
Read 2 more answers
A box (m = 20 kg) is sliding on a horizontal surface. it is connected to a massless hook by a light string passing over a massle
Varvara68 [4.7K]

mass of the box = 20 kg

force of friction on the box due to surface

F_s = \mu_s N

F_s = 0.80 * 20 * 9.8

F_s = 156.8 N

similarly kinetic friction on it

F_k = \mu_k N

F_k = 0.30* 20 * 9.8

F_k = 58.8 N

now the weight of the suspended block will be

W = mg = 15*9.8 = 147 N

so here the weight of the suspended block is less than the limiting friction on it

So here we will say that friction will counter balance the weight of the suspended block and it will not move at all

So acceleration of the box will be zero

5 0
3 years ago
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