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sergey [27]
4 years ago
5

Sports car goes from a velocity of zero to a velocity of 12 m/s East in two seconds. What is the cars acceleration?

Physics
1 answer:
bogdanovich [222]4 years ago
7 0

Answer:

6 m/sec

Explanation:

12/2=6

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EastWind [94]
The data from our experiment.

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A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha
Paha777 [63]

Answer:

3.At equilibrium, its instantaneous velocity is at maximum

Explanation:

The motion of a mass on the end of a spring is a simple harmonic motion. In a simple harmonic motion, the total mechanical energy of the system is constant, and it is sum of the elastic potential energy (U) and the kinetic energy of the mass (K):

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 = const.

where

k is the spring constant

x is the displacement of the spring from equilibrium

m is the mass

v is the speed

As we see from the formula, since the total energy E is constant, when the displacement (x) increases, the speed (v) increases, and viceversa. Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

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3 years ago
Contrast your Reflection from the back of a shiny spoon and from a plane mirror.​
julsineya [31]
Ok so what happened?
6 0
3 years ago
A suitcase is pulled 28 feet along a flat sidewalk with a constant upward force of 80 lb at an angle of 23degrees with the horiz
Elenna [48]

Answer:

2795.3 J

Explanation:

distance, d = 28 feet = 8.53 m

Force, F = 80 lb = 356 N

Angle, θ = 23°

Work = F x d x cos θ

W = 356 x 8.53 x cos 23

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Thus, the work done is 2795.3 J.

5 0
4 years ago
A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to th
Anna [14]

Answer:

1250\sqrt{3}

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be \frac{\sqrt{3}}{2}.

Therefore, the force pulling the box in the cable's direction is:

\frac{2500\sqrt{3} }{2}  = 1250\sqrt{3}

<em />

<em>If you have any questions feel free to comment.</em>

<em />

<em>Have a great one and mark brainliest if it helped, please</em>

8 0
2 years ago
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