The temperature of the countertop changes by 0.032 °C
The quantity of heat transferred to the countertop is given by
Q = CΔT where Q = quantity of heat transferred to the countertop = 5000 J = 5 kJ, C = heat capacity of the countertop = 158.5 kJ/°C and ΔT = temperature change of the countertop.
Since we require the temperature change of the countertop, we make ΔT subject of the formula.
So, ΔT = Q/C
So, substituting the values of the variables into the equation, we have
ΔT = Q/C
ΔT = 5 kJ/158.5 kJ/°C
ΔT = 0.032 °C
So, the temperature of the countertop changes by 0.032 °C
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Answer: pH of HCl =5, HNO3 = 1,
NaOH = 9, KOH = 12
Explanation:
pH = -log [H+ ]
1. 1.0 x 10^-5 M HCl
pH = - log (1.0 x 10^-5)
= 5 - log 1 = 5
2. 0.1 M HNO3
pH = - log (1.0 x 10 ^ -1)
pH = 1 - log 1 = 1
3. 1.0 x 10^-5 NaOH
pOH = - log (1.0 x 10^-5)
pOH = 5 - log 1 = 5
pH + pOH = 14
Therefore , pH = 14 - 5 = 9
4. 0.01 M KOH
pOH = - log ( 1.0 x 10^ -2)
= 2 - log 1 = 2
pH + pOH = 14
Therefore, pH = 14 - 2 = 12
Answer: 24 moles of
are produced.
Explanation:
To calculate the moles :

According to stoichiometry :
1 mole of
is accompanied with = 1 mole of 
Thus 24 moles of
is accompanied with =
of 
Thus 24 moles of
are produced.
A decrease in the amount of gas in a container will mean a decrease in pressure.
Answer:
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