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3 years ago

In which situation is no work considered to be done by a force?

Physics

1 answer:

Ber [7]3 years ago

7 0

Answer:

O B. when the angle between the force and displacement is 90°

Explanation:

<h3>work defined as $w = f cos Ф * d$ . </h3><h3>work can only be done if object moves(displacement) in the direction of force. now a quick one. if you since the varrious angles into the cosine, you would see that Cos 90 will give zero which implies that no work is done. Again, angle means it is perpendicular and so it is not in the direction of force.</h3>

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For many years Colonel John P. Stapp, USAF, held the world's land speed record. He participated in studying whether a jet pilot

Margarita [4]

Answer:

(a) -202 m/s²

(b) 198 m

Explanation:

Given data

Initial speed (v₀): 283 m/s

$\frac{632mi}{h} .\frac{1609.34m}{1mi} .\frac{1h}{3600s} =283m/s$

Final speed (vf): 0 (rest)

Time (t): 1.40 s

(a) The acceleration (a) is the change in the speed over the time elapsed.

a = (vf - v₀)/t = (0 - 283 m/s)/ 1.40s = -202 m/s²

(b) We can find the distance traveled (d) using the following kinematic expression.

y = v₀ × t + 1/2 × a × t²

y = 283 m/s × 1.40 s + 1/2 × (-202 m/s²) × (1.40 s)²

y = 198 m

3 0

3 years ago

A pure sound wave, generated by a tuning fork, is considered a periodic wave. Which statement is true for this tuning fork sound

soldier1979 [14.2K]

Answer : Every wave has the same wave pattern.

Explanation : A pure sound wave has a single frequency and its generated by a tuning fork . The sound wave is a simple periodic wave.

When an object such as a guitar push and pull on the around it. When it pushes on the air, then the pressure increases and when it pull on the air, then the pressure decreases and sound waves are formed.

Hence, sound wave has the same wave pattern.

4 0

3 years ago

Read 2 more answers

What does the stirrup press against

AveGali [126]

We need a system to use those air vibrations to push against the surface of the inner ear fluid.

7 0

3 years ago

un conductor de plata (p=1,6x10°-6ohm x m) tiene una seccion de 5x10°-6 m°2 y una longitud de 110 m . calcular la resistencia

Alexus [3.1K]

Responder:

35,2 ohm.

Explicación:

Dado:

La resistencia específica del conductor es,

La longitud del conductor es,

El área de la sección transversal del conductor es,

Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

Por lo tanto, la resistencia se puede expresar como:

$R=\frac{\rho\times l}{A}$