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Inessa05 [86]
2 years ago
5

- A ball is thrown at a wall 50 meters away. It takes the ball 5 seconds to get to

Physics
1 answer:
zimovet [89]2 years ago
7 0

Answer:

<h3>The answer is 10 m/s</h3>

Explanation:

The average speed of the ball can be found by using the formula

v =  \frac{d}{t}  \\

d is the distance

t is the time taken

From the question we have

v =  \frac{50}{5}  \\

We have the final answer as

<h3>10 m/s</h3>

Hope this helps you

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Select the correct answer from each drop-down menu. complete the sentence to describe the distance and ruler postulates. between
Tresset [83]

This question is an illustration of the distance postulate.

<h3>What is distance postulate ?</h3>

The distance between any two different points equates to a single positive real integer, according to the postulate of distance.

The full text is: The distance is a positive unique integer between every pair of different locations.

Consider two separate points A and B as an example.

The distance between A and B is the integer that represents the size of A and B.

The positive number (i.e. the distance) between A and B would be:

d= B-A

d = 6 - 1

d = 1

Read more about distance postulate at:

brainly.com/question/16765541

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3 0
2 years ago
ITS TIMED PLEASE HELP !!!!!
dusya [7]

Answer: direct linear

Explanation:

3 0
3 years ago
2. A ball tied to a pole by a rope swings in a circular path with a centripetal acceleration of 2.7 m/s. If the ball has a
Helga [31]

Answer: The diameter of the circular path is 2.96m

Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.

Centripetal acceleration = 2.7m/s^2

Tangential speed = 2.0m/s

Radius = 2.0^2 / 2.7 = 4/2.7

= 1.48m

Diameter = radius*2

= 1.48*2 = 2.96m.

3 0
3 years ago
Suppose you push a hockey puck of mass m across frictionless ice for a time \Delta t, starting from rest, giving thepuck speed v
bazaltina [42]

Answer:

1. t_2 = 2t_1

2. t_2 = t_1\sqrt{2}

Explanation:

1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.

In Newton's 2nd law: F = ma

where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.

a_1 = 2a_2

Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time

t = v / a_1

Now that acceleration is halved:

t = \frac{v}{2a_2}

\frac{v}{a_2} = 2t

You would need to push for twice amount of time t_2 = 2t_1

2. The distance traveled by the puck is as the following equation:

d = at^2

So if the acceleration is halved while maintaining the same d:

\frac{d_1}{d_2} = \frac{a_1t_1^2/2}{a_2t_2^2/2}

As d_1 = d_2, then d_1/d_2 = 1. Also a_1 = 2a_2

1 = \frac{2a_2t_1^2}{a_2t_2^2}

t_2^2 = 2t_1^2

t_2 = t_1\sqrt{2}\approx 1.14t_1

So t increased by 1.14

7 0
3 years ago
What is the name and symbol of the element in the second row and fourteenth column of the periodic table? Hint: Review your peri
Papessa [141]
The answer is Carbon. Beyond being the only element listed here that is located in the second row, it is also in the fourteenth column of the table if you count from left to right. Hope this helps!
4 0
3 years ago
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