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3 years ago

- A ball is thrown at a wall 50 meters away. It takes the ball 5 seconds to get to

Physics

1 answer:

zimovet [89]3 years ago

7 0

Answer:

<h3>The answer is 10 m/s</h3>

Explanation:

The average speed of the ball can be found by using the formula

$v = \frac{d}{t} \\$

d is the distance

t is the time taken

From the question we have

$v = \frac{50}{5} \\$

We have the final answer as

Hope this helps you

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As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 3.19 back-and-forth cy

lesantik [10]

Explanation:

Since, it is given that one hand completes 3.19 vibrations in 8.46 sec. Therefore, in one second the number of vibrations will be as follows.

$\frac{3.19}{8.46}$

= 0.377 vibrations

Hence, frequency (f) = 0.38 Hz

Now, formula to calculate the speed is as follows.

v = $f \times \lambda$

or, $\lambda = \frac{v}{f}$

= $\frac{0.6 cm/s}{0.38}$

= 1.57 cm

Thus, we can conclude that the wavelength is 1.57 cm.

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3 years ago

Sallys physical education teacher timed her run and recorded the time and distance in the table below. What is her average speed

Fudgin [204]

Answer: B) 2.5 m/s

Explanation: Find the average of the time and distance, and see how far they go in only 1 second.

1 + 2 + 3 + 4 + 5 = 15
15 divided by 5 = 3

3 seconds

2 + 5 + 7 + 10 + 12 = 36
36 divided by 5 = 7.2

7.2m per 3 seconds.

7.2 divided by 3 = 2.4

Therefore, the answer is technically 2.4m/s

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4 years ago

When will electric charges flow?

Norma-Jean [14]

C. when the circuit is closed

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3 years ago

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When testing a home for radon, where is the most likely place for the highest detected level? A) the basement, due to ground see

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Explanation:

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3 years ago

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A gymnast is swinging on a high bar. The distance between his waist and the bar is 0.905 m, as the drawing shows. At the top of

Citrus2011 [14]

Answer:

5.959 m/s

Explanation:

m = Mass of gymnast

u = Initial velocity

v = Final velocity

$h_i$ = Initial height

$h_f$ = Final height

From conservation of Energy

$\frac{1}{2}mv^2+mgh_f=\frac{1}{2}mu^2+mgh_i\\\Rightarrow\frac{1}{2}mv^2+mg0=\frac{1}{2}m0^2+mgh_i\\\Rightarrow \frac{1}{2}mv^2=mgh_i\\\Rightarrow v=\sqrt{2gh_i}$

$h_i=2r$

$v=\sqrt{4gr}\\\Rightarrow v=\sqrt{4\times 9.81\times 0.905}\\\Rightarrow v=5.959\ m/s$

Velocity of gymnast at bottom of swing is 5.959 m/s

5 0

3 years ago