Answer:
Displacement: 2.230 km Average velocity: 1.274
Explanation:
Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:
- 0.916 km due east is an horizontal direction and cane be seen as direction towards the negative side of X-axis.
- 0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
- 3.52 km in a direction of 49.7° has components on X and Y axes. It is necessary to break it down using trigonometry,
First of all. We need to sum all the X components and all the Y componets.
∑
⇒ ∑![Sx = [tex]3.52cos(49.7) - 0.916](https://tex.z-dn.net/?f=Sx%20%3D%20%5Btex%5D3.52cos%2849.7%29%20-%200.916)
∑
∑
⇒ ∑
∑
The total displacement is calculated using Pythagoeran therorem:
⇒

With displacement calculated, we can find the average speed as follows:
⇒ 

Vaginal opening. areola is the part of the breast.
One side of the wave changes speed before the other side, causing the wave to move
Answer:
<h3>1.43m/s²</h3>
Explanation:
According to newtons second law.
F = mass * acceleration
If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg
Force applied = 1N
acceleration = Force/mass
Substitute the values and get acceleration
acceleration = 1/0.7
acceleration = 1.43m/s²
Hence the magnitude of the acceleration of the robot is 1.43m/s²