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Leya [2.2K]
3 years ago
12

Susan Marciano invested part of her $29,000 bonus in a fund that paid a 10% profit and invested the rest in a stock that suffere

d a 4% loss. Find the amount of each investment if her overall net profit was $1,080 The amount invested at 10% is? The amount invested in stock is:_____
Mathematics
1 answer:
dangina [55]3 years ago
3 0

Answer:The amount invested at 10% is $16000

The amount invested in stock is $13000

Step-by-step explanation:

Let x represent the amount of money that Susan invested in the fund that paid a 10% profit.

Let y represent the amount of money that Susan invested in the stock that that suffered a 4% loss.

Total amount invested is 29000. This means that

x + y = 29000

The profit made on the fund is

10/100 × x = 0.1x

The loss made on the stock is

4/100 × y = 0.04y

if her overall net profit was $1,080, it means that

0.1x - 0.04y = 1080 - - - - - - - -1

Substituting x = 29000 - y. It becomes

0.1(29000 - y) - 0.04y = 1080

2900 - 0.1y - 0.04y = 1080

- 0.1y - 0.04y = 1080 - 2900

- 0.14y = - 1820

y = - 1820/ - 0.14 = 13000

Substituting y = 13000 into x = 29000 - y, it becomes

x = 29000 - 13000

x = 16000

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A jeweler is dividing
Anuta_ua [19.1K]

Answer: OPTION D:  \frac{3}{32}

Step-by-step explanation:

By definiton, fractions have the following form:

\frac{a}{b}

Where "a" is called numerator and "b" is the denominator. The numerator and the denominator are Integers.

 In order to solve this exercise you need to remember de Division of fractions:

\frac{a}{b}\div\frac{d}{e}=\frac{a}{b}*\frac{e}{d}=\frac{a*e}{b*d}

In this case, according to the information given in the exercise, you know that \frac{3}{8}\ lb of rubies are divided into 4 lots.

Therefore, in order to calculate the weight in pounds of each lot, you need to divide \frac{3}{8}\ lb  by 4.

Then, you get the following result:

\frac{3}{8}\ lb\div4=(\frac{3}{8}\ lb) (\frac{1}{4})=\frac{3}{8*4}\ lb=\frac{3}{32} \ lb

As you can notice, this result matches with the Option D.

5 0
3 years ago
GAIQNFKDKER HELP PLZ
Softa [21]

Answer:

it's the first answer

Step-by-step explanation:

literally every other answer is ruled out because D is the greatest variable and can't be smaller than anything else

3 0
3 years ago
26 POINTS !! PLEASE HELP (no fake answers please !)
snow_lady [41]
The answer is 13 because when you plug it all in you get the answer 24(1/2) is 12 and 2(7) is 14 add them together you get 26 now for the bottom 1/4(8) is 2 so 26 over 2 is 13 100% correct promise
8 0
3 years ago
Read 2 more answers
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
Susie bought 434 pounds of cherries at the store. She ate 58 of a pound on the way home. How many pounds of cherries does Susie
Molodets [167]
Susie bought 434 pounds, and ate 58pounds

so, 434-58= 376

> 376pounds left

6 0
3 years ago
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