1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kherson [118]
3 years ago
11

The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear

ance of Br2 is ________ M s-1. The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appearance of Br2 is ________ M s-1.
a. 0.0700
b. 1.28
c. 0.0196
d. 0.280
e. 0.374
Chemistry
1 answer:
djverab [1.8K]3 years ago
6 0

Answer: The rate of appearance of Br_2 is 0.0700Ms^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = -\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2 = \frac{1d[H_2]}{dt}

Rate in terms of appearance of Br_2 = \frac{1d[Br_2]}{dt}

-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}

Given :

-\frac{1d[HBr]}{dt}=0.140Ms^{-1}

The rate of appearance of Br_2;

\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}

Thus rate of appearance of Br_2 is 0.0700Ms^{-1}

You might be interested in
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
Why is scientific notation useful?
BlackZzzverrR [31]
It condenses very long strings of numbers while retaining the general accuracy of the figure.
8 0
3 years ago
Read 2 more answers
A solution is prepared by dissolving 23.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
alekssr [168]
<span>The density of the solution =1.05 g/ml.
</span><span>The total mass of the resulting solution is = 398.7 g (CaCl2 + water)
</span>
Find moles of CaCl2 and water.
Molar mass of CaCl2 = 110 (approx.)

Moles of CaCl2 = 23.7 / 110  = 0.22
so, moles of Cl- ion = 2 x 0.22 = 0.44  (because each molecule of CaCl2 will give two Cl- ions)
Moles of water = 375 / 18 = 20.83

Now, Mole fraction of CaCl2 =  (moles of CaCl2) / (total moles)

total moles = moles of Cl- ions + moles of Ca2+ ions + moles of water

                  = 0.44 + 0.22 + 20.83

=21.49


So, mole fraction = 0.44 / (21.49) = 0.02

Guess what !!! density is not used. No need

4 0
3 years ago
Read 2 more answers
Methane reacts with chlorine in the presence of ultraviolet light
earnstyle [38]

Answer:

When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight - a substitution reaction occurs and the organic product is chloromethane. CH 4 + Cl 2 → CH 3 Cl + HCl However, the reaction doesn't stop there, and all the hydrogens in the methane can in turn be replaced by chlorine atoms.

Explanation:

hope it help i try best

7 0
2 years ago
If the density of an object is 5 g/cm3 and it takes up 7 cm3 of space, calculate the mass?
statuscvo [17]

Answer:

<h2>The answer is option A</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 7 cm³

density = 5 g/cm³

The mass of the object is

mass = 5 × 7

We have the final answer as

<h2>35 g</h2>

Hope this helps you

8 0
3 years ago
Other questions:
  • The way metals surface reflects light is called
    7·2 answers
  • I need help with this
    8·1 answer
  • You compared the color of the solutions in three test tubes that initially contained 3 mL of 0.1 M ammonium hydroxide and a few
    11·1 answer
  • Give the chemical symbol for the element with the ground‑state electron configuration [ Ar ] 4 s 2 3 d 1 . symbol: Determine the
    10·1 answer
  • 1.00 mL of a 250.0 µM solution of KCl is diluted to 50.0 mL. What is concentration of this solution?
    12·1 answer
  • How many moles are in 88.1 of magnesium
    9·1 answer
  • How many atoms are there in 5.70 mol of Mg
    15·1 answer
  • If 200 g of water is heated from 20 C to 40 C, then what is the heat added in kilocalories (same as food calories)?
    9·1 answer
  • I need help ASAP
    14·1 answer
  • 1. What is an air mass? 2. What 2 factors characterize an air mass? 3. What determines the two characteristics of an air mass? 4
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!