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4 years ago

Please help! Show all work.

Mathematics

1 answer:

Morgarella [4.7K]4 years ago

8 0

First, let's work with the denominator alone:

4⁻⁴ = 1 / 4⁴ = 1/256 .

The original problem is the reciprocal of that = 256.

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Plz help ill give extra points

zalisa [80]

Answer:

I wasnt sure of the question but i hope this is right

Step-by-step explanation:

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3 years ago

Read 2 more answers

A 6-foot tall man casts a shadow that is 12 feet long. What is the measure of the sun's angle of elevation? Enter your answer, r

Masteriza [31]

Answer:

$27^{\circ}$

Step-by-step explanation:

Let x represent the sun's angle of elevation.

We have been given that a 6-foot tall man casts a shadow that is 12 feet long.

Upon looking at our attachment we can see that man and his shadow forma a right triangle with respect to ground, where height of man is opposite side and his shadow is adjacent side.

Since tangent relates opposite side of a right triangle with adjacent, so we can set an equation as:

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

$\text{tan}(x)=\frac{6}{12}$

$\text{tan}(x)=\frac{1}{2}$

Using arctan we will get,

$x=\text{tan}^{-1}(\frac{1}{2})$

$x=26.565051177078^{\circ}\approx 27^{\circ}$

Therefore, the measure of the sun's angle of elevation is 27 degrees.

3 0

4 years ago

((12 divided by 3)2-(18 divide by 3 to the power of 2))x(4 divided 2)

makvit [3.9K]

Answer:

(12/3)*2-(18/3^2)*(4/2)=4

Step-by-step explanation:

12/3=4

18/3^2=2

4/2=2

(4*2)-(2*2)

^ ^

8-4=4

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3 years ago

a company pays its employees a base salary of $1000 every other week plus $30 for each sale write the equation to how much a pay

ivann1987 [24]

Part 1: Equation is p=1000+30x
Part 2:
a) 1720=1000+30x
b)1720-1000=30x
c)720=30x
d)720/30=x
e)24 sales = x

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3 years ago

How do you solve √125÷√5

nordsb [41]

$\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5$

8 0

3 years ago