John wants to measure the width of a stream using the methods he has learned in geometry. He puts a stake in the ground opposite
a big tree. The steps John would use to find the measure he wants are given below in random order. Put the number next to the following statements to indicate the proper sequence John would use to find the measure he wants.
The steps John would use to measure the width of the stream are given below in random order. Put the number next to the following statements to indicate the proper sequence John would use to find the measure he wants.
1. Step 1
5
John measures the distance between the two stakes.
2. Step 2
2
John uses a compass to walk away from the stake at a right angle.
3. Step 3
4
John multiplies the distance between the two stakes by 1.7 to find the distance.
4. Step 4
3
John drives a second stake in the ground.
5. Step 5
1
On the path John walks until he finds a line of sight to the tree that equals 60 degrees.
6. Step 6
6
John drives a stake opposite the tree to establish a line between two points.
The steps John would use to measure the width of the stream are given below in random order. Put the number next to the following statements to indicate the proper sequence John would use to find the measure he wants.
1. Step 1
5
John measures the distance between the two stakes.
2. Step 2
2
John uses a compass to walk away from the stake at a right angle.
3. Step 3
4
John multiplies the distance between the two stakes by 1.7 to find the distance.
4. Step 4
3
John drives a second stake in the ground.
5. Step 5
1
On the path John walks until he finds a line of sight to the tree that equals 60 degrees.
6. Step 6
6
John drives a stake opposite the tree to establish a line between two points.
2 answers:
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Answer:
The designed life should be of 21,840 vehicle miles.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.
This means that
Find its designed life if a .97 reliability is desired.
The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.
The designed life should be of 21,840 vehicle miles.