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Delicious77 [7]
3 years ago
9

What is the focus of the parabola (y-3)^2=8(x-5)?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0
Hello,

Let's suppose y'=y-3
and x'=x-5
Parabola  become y'²=8x' whose focus is (8/4,0)=(2,0)

y=y'+3==>y=0+3=3
x=x'+5==>x=2+5=7
Focus is (7,3)
Rem for parabola y²=kx focus is (k/4,0)


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