Answer:
$17 on food per person
Step-by-step explanation:
The cost of parking a car is $5
Assuming that the friends used one car, then the parking cost=$5
Admission cost is 19
For three people, Admission cost =19*3=57
TOTAl COSTS=Parking cost+Admission cost
TOTAl COSTS=57+5=62
Remaining amount can be used for food
FOOD= 113-62=51
Therefore each person can spend 51/3=$17 on food
I hope this was helpful and clear to follow
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
Answer: (7+1/7) *(7+7)
Step-by-step explanation:
9514 1404 393
Answer:
₹14000
Step-by-step explanation:
Let c represent the cost price, and m represent the marked price.
c × (1 +40%) = m
m × (1 -15%) - c = ₹1900
Using the first expression for m, the second equation becomes ...
1.40c×0.85 -c = ₹1900
0.19c = ₹1900
c = ₹1900/0.19 = ₹10000
Then the marked price was ...
m = 1.40c = 1.40×₹10000 = ₹14000
The marked price was ₹14000.
_____
The selling price was ₹11900.