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Delvig [45]
3 years ago
9

While working out, a man performed 200 j of work in 3 seconds. What was his power?

Physics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer: 66.7 watts

Explanation:

Given that:

Work performed by man = 200 j

Time taken to do work = 3 seconds.

Power = ?

Recall that power is the rate of work done per unit time

i.e Power = work/time

Power = 200J / 3seconds

Power = 66.7 watts

Thus, his power is 66.7 watts

frosja888 [35]3 years ago
5 0

Answer: P= w/t so P= 200/ 3= 66.67 w

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Answer:

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4 years ago
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Elis [28]

Answer:

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bagirrra123 [75]

Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

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T = Radiated surface temperature

\lambda_{max} = peak wavelength

(a)

here,

\lambda_{max} = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}

<u>T = 2987.6 k</u>

(b)

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\lambda_{max} = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}

<u>T = 19986.2 k</u>

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I hope this helps!

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