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Delvig [45]
3 years ago
9

While working out, a man performed 200 j of work in 3 seconds. What was his power?

Physics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer: 66.7 watts

Explanation:

Given that:

Work performed by man = 200 j

Time taken to do work = 3 seconds.

Power = ?

Recall that power is the rate of work done per unit time

i.e Power = work/time

Power = 200J / 3seconds

Power = 66.7 watts

Thus, his power is 66.7 watts

frosja888 [35]3 years ago
5 0

Answer: P= w/t so P= 200/ 3= 66.67 w

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A balloon filled with helium gas has an average density of rhob = 0.22 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.
MissTica

Answer:

a=g\left(\frac{\rho_a}{\rho_b}-1\right)

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F_b = Buoyant force

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\rho_b = Density of balloon = 0.22 kg/m³

v_a = Volume of air

v_b = Volume of balloon

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g = Acceleration due to gravity = 9.81 m/s²

The net force acting on the balloon is

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The equation is a=g\left(\frac{\rho_a}{\rho_b}-1\right)

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