Answer:
Well..
Explanation:
That's impossible. I know because I once weighed 11.1 kN, and I was temporarily immobile. It's probably the same for a car, and therefore it can not be "traveling" anywhere at all.. unless you put the car on an airplane or a boat or something.
Answer:
a) 104
b) 106
c) 884 mA
Explanation:
The ratio of the transformer is given by:

We need to know the current in the primary in order to obtain the power applied.

The current rating of the fuse is the current on the primary, 884mA as we calculated before in order to obtain the power.
That would be the Earth's rotation. Hope this helps!
Answer:
i think the answer is 0.001m³
Answer:
311,850 N
Explanation:
We can solve the problem by using Newton's second law:

where
F is the net force applied on an object
m is the mass of the object
a is its acceleration
For the object in this problem,
m = 27 kg

Substituting, we find the force required:
