The time taken by the stone to hit the ground would be 5.12 seconds.
<h3>What are the three equations of motion?</h3>
There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s
height(S) = 156.8 meters
initial velocity(u) = -19.6 m/s
acceleration(a) = 9.81 m/s²
By using the second equation of motion given by newton
S = ut + 1/2at²
S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds
156.8= -19.6t + 9.81t²
t = 5.12 seconds
Thus, the time taken by the stone to hit the ground would be 5.12 seconds.
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Answer:
v = -10⁵ m/s
Explanation:
given,
speed of asteroid,v' = 100 m/s
mass of superman = m
mass of asteroid,M = 1000 m
recoil velocity of superman,v= ?
using conservation of momentum.
m u + M u' = m v + M v'
initial velocity of asteroid and superman is equal to zero
0 + 0 = m v + 1000 m x 100
m v = -100000 m
v = -10⁵ m/s
superman's velocity after throwing the asteroid is equal to v = -10⁵ m/s
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Answer:
The initial volume of the system is 2.7 L
Explanation:
The change in internal energy is given by;
ΔU = Q - W
where;
Q is the heat absorb from the surrounding
W is the work done by the system
Given;
ΔU = -107.6 J
Q = 59 J
W = ?
W = Q- ΔU
W = 59J - (-107.6)
W = 166.6 J
Work done is given by;
W = PΔV
W = P(V₂ - V₁)
101.325 Joules = 1 L.atm
166.6 Joules = ?
= 1.644 L.atm
1.644 L.atm = 0.543 atm(57.7L - V₁)
57.7L - V₁ = (1.644 L.atm) / (0.543 atm)
57.7L - V₁ = 3.0 L
V₁ = 57.7L - 3.0 L
V₁ = 2.7 L
Therefore, the initial volume of the system is 2.7 L
Answer:
101 meters
Explanation:
Distance traveled by the tourist:
d = 3.60 m/s × t
Distance traveled by the bear:
d + 39.3 m = 5.00 m/s × t
Substitute:
3.6 t + 39.3 = 5 t
39.3 = 1.4 t
t = 28.1
d = 101
