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Korolek [52]
3 years ago
7

Will mark as brainliest if correct!!!!

Physics
1 answer:
Alex787 [66]3 years ago
4 0

Because light travels more quickly in D. glass than in diamond

Explanation:

Refraction is a phenomenon of light waves that occurs when a light way crosses the boundary between two different mediums. When this happens, the wave changes its direction and also its speed. In particular, there is an equation (called Snell's law) that descrives the direction of the refracted ray relative to the incident ray:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1, n_2 are the index of refraction of medium 1 and 2, respectively

\theta_1 is the angle of incidence (the angle between the incident ray and the normal to the boundary between the two mediums)

\theta_2 is the angle of refraction (the angle between the refraction ray and the normal to the boundary between the two mediums)

The equation can also be written as

\frac{sin \theta_2}{sin \theta_1}=\frac{n_1}{n_2} (1)

The index of refraction of a medium is equal to

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in the medium

Using this, we can rewrite (1) as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1 = \frac{v_2}{v_1} sin \theta_1

where v_2 is the speed of light in the 2nd medium and v_1 the speed of light in the 1st medium.

Here we are comparing two situations:

1) Light passing from air to glass

2) Light passing from air to diamond

We are said that light is refracted by a greater amount when it passes from air to diamond: this means that in situation 2), the value of sin \theta_2 is smaller than in situation 1) (keep in mind that the angle is measured with respect to the normal, so a larger refraction means a smaller angle, since the refracted ray bends towards the normal). And therefore, this means that the ratio \frac{v_2}{v_1} is smaller for case 2) rather than for case 1): since v_1 in both cases is the same (the speed of light in air), this means that light travels more quickly in glass than in diamond, so option D.

In fact, by comparison:

Index of refraction in glass: 1.66

Index of refraction in diamond: 2.41

Which means that light travels faster in glass.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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A. A ball is thrown directly up with an initial speed of 4.00 m/s at y = 0. What is the maximum height h that it achieves, and w
sveta [45]

Answer:

A)     t = 0.40816 s , y = 0.916 m

Explanation:

A) For this problem we use the kinematic relations

           v = v₀ - g t

the highest point zero velocities (v = 0)

           t = (v₀-v) / g

           t = (4 - 0) / 9.8

           t = 0.40816 s

to calculate the height let's use

          v² = v₀² - 2 g y

          y = vo2 / 2g

           y = 4 2 / (2 9.8)

          y = 0.916 m

To find the number of photos, we can use a direct proportions rule, if you take 30 photos in a second in 0.40816 s how many photos does it take

          # _photos1 = 0.40916 (30/1)

          # _photos1 = 12

yes i take 120 fps

          #_fotod = 0.40916 (120/1)

          #photos = 5.87 10³

 

B) The ball is released from a latura h how long it takes to reach the floor

           v² = v₀² + 2 g y

where the initial velocity is zero and the velocity with which the expert leaves is equal to the velocity with which v = 4 m / s leaves

            v² = 2gy

             v = √ (2 9.8 0.916)

             v = √ (2.1397 101)

             v = 4.6257 m / s

c) we ask us for the time for latura

             y = L / 2

             y = 0.916 / 2

             y = 0.458 m

now we can use the formula

             y = v₀ t - ½ g t²

           0.458 = 4.00 t - ½ 9.8 t²

            4.9 t² - 4t + 0.458 = 0

            t² -0.8163 t +0.09346 = 0

we solve second degree execution

           t = [0.8163 ±√ (0.8163² - 4 0.09346)] / 2

           t = [0.8163 ± 0.540] / 2

           t₁ = 0.678 m

           t₂ = 0.2763 m

the shortest time is for when the ball goes up and the longest when it goes down

D) the graph of vs Vs is expected to be a closed line

and the graph of position versus time a parabola

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3 years ago
Two electrons with a charge of magnitude 1.6×10-19 C in an atom are separated by 1.5×10-10 m, the typical size of an atom. What
vesna_86 [32]

Answer:

1.02\cdot 10^{-8} N, repulsive

Explanation:

The magnitude of the electric force between two charged particles is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges of the two particles

r is the separation between the two charges

The force is:

- repulsive if the two charges have  same  sign

- Attractive if the two charges have opposite signs

In this problem, we have two electrons, so:

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the two electrons

r=1.5\cdot 10^{-10} m is their separation

Substituting into the formula, we find the electric force between them:

F=(8.99\cdot 10^9)\frac{(1.6\cdot 10^{-19})^2}{(1.5\cdot 10^{-10})^2}=1.02\cdot 10^{-8} N

And the force is repulsive, since the two electrons have same sign charge.

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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

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maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

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now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

   v₂² = 31061.79

   v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

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Vanyuwa [196]
The answer is the starting friction
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