Answer:
0.1835m/s
Explanation:
The formula for calculating the speed of wave is expressed as;
v = fλ
f is the frequency - The number of oscillations completed in one seconds
If 22 waves pass the boat every 60 seconds,
number of wave that passes in 1 seconds = 22/60 = 0.367 waves
Therefore the frequency f of the wave is 0.367Hertz
λ (wavelength) is the distance between successive crest and trough of a wave
λ = 0.5m
Substitute the given values into the formula
v = fλ
v = 0.367 * 0.5
v = 0.1835
Hence the speed of the waves is 0.1835m/s
Explanation:
Consider the kinematic equation,

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

through simple algebra we get

where this is the distance traveled in meters.
Answer:

Explanation:
In this process energy must be conserved. On the initial stage, there will be only gravitational potential energy, while on the final stage there will be only elastic potential energy, so they will be equal. We write this as:

Which is the same as:

So we can obtain our mass from there, and for our values:

3.11 is the answer I think