True or false forces in a force pair never cancel each other out

Suppose a uniform electric field of 4 N/C is in the positive x direction. When a charge is placed at and fixed to the origin, th

Yuliya22 [10]

Answer:

E_total = 3 N / A

Explanation:

The electric field is a vector magnitude so when adding we must use vectors, in this case as the initial field E = 4N / c goes towards the axis axis and the field created by the fixed charge (E1) is also on the axis x we can add in scalar form.

E_total = E + E₁

the expression for the field of a point charge is

E₁ = k q₁ / r²

for the point x = 2m, they do not say that the total field is zero, so the charge q1 must be negative

E_total = E -k q₁ / r₂

we substitute

0 = E - k q₁ / r²

q₁ = $\frac{E r^2}{k}$

let's calculate

q₁ = $\frac{4 \ 2^2}{9 \ 10^{-9}}$

q₁ = 1.78 10⁻⁹ C

now we can calculate the field for position x = 4 m

E_total = 4 - 9 10⁹ 1.78 10⁻⁹ / 4²2

E_total = 3 N / A

8 0

2 years ago

Một vật dao động điều hòa với phương trình x= 4cos(6πt) cm. Kể từ khi vật bắt đầu dao động, thời điểm vật qua a) vị trí cân bằng

dezoksy [38]

Answer:

what are you saying.........

......

7 0

2 years ago

Using the scientific definition of work, does moving an object a greater amount of distance always require a greater amount of w

tester [92]

The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.