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3 years ago

Johannes Kepler, an apprentice of Brahe, believed in the heliocentric universe but rejected past astronomers' belief in

2 answers:

5 0

So the question is in what did johannes Kepler reject since he believed in the heliocentric universe. So heliocentric system is a system where the sun is in the center of the Solar system. Geocentric system is the system where Earth, not Sun is in the center of our system. He was against Geocentric system.

Vlada [557]3 years ago

5 0

Answer:

circular orbital pattern.

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Anna drives north at a speed of 50 km/h for the first hour. Then, she drives north for a second hour but slows down to 30 km/h.

8090 [49]

Answer:

The correct answer is A The distance is greater in the first hour because her speed is faster.

Explanation:

During the first hour, Anna is driving at a speed of 50 km/h. During the second hour, she is only driving at a speed of 30 km/h. The faster she goes, the farther she will go.

Hope this helps,

♥A.W.E.S.W.A.N.♥

8 0

3 years ago

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The picture below shows a wheelbarrow. Using a wheelbarrow can make it easier to lift a heavy object by

timofeeve [1]

Answer:

B IS CORRECT

Explanation:

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3 years ago

Which benefit outweighs the risks in the technological design of headphones?

Dmitriy789 [7]

Answer:

The Answer is A They can damage hearing.

Explanation:

I took the Test

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3 years ago

Electric fields up to 2.00 × 10 5 N/C have been measured inside of clouds during electrical storms. Neglect the drag force due t

katrin2010 [14]

Answer:

$1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

23.4843749996 m

Yes

Explanation:

E = Electric field = $2\times 10^5\ N/C$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of proton= $1.67\times 10^{-27}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

Acceleration is given by

$a=\dfrac{Eq}{m}\\\Rightarrow a=\dfrac{2\times 10^5\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}\\\Rightarrow a=1.9161676647\times 10^{13}\ m/s^2$

Dividing by g

$\dfrac{a}{g}=\dfrac{1.9161676647\times 10^{13}}{9.81}\\\Rightarrow a=1.9532799844\times 10^{12}g$

The acceleration is $1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(0.1\times 3\times 10^8)^2-0^2}{2\times 1.9161676647\times 10^{13}}\\\Rightarrow s=23.4843749996\ m$

The distance is 23.4843749996 m

The gravitational field is very small compared to the electric field so the effects of gravity can be ignored.

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3 years ago

Calculate the gravitational potential energy of 3kg book sitting on shelf 4m high

likoan [24]

Answer:

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Explanation:

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3 years ago

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