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s2008m [1.1K]
3 years ago
12

Which circuits correctly show Ohm's law?

Physics
2 answers:
Elodia [21]3 years ago
6 0
Ohm’s Law:
V = IR
V = battery voltage, I = current, R = resistance

Top-left circuit:
V = 25V, I = 5A, R = 5ohm
25 = 5•5
25 = 25
This circuit is correct.

Top-right circuit:
V = 18V, I = 6A, R = 4ohm
18 = 6•4
18 =/= 24
This circuit is incorrect.

Bottom-left circuit:
V = 56V, I = 7A, R = 8ohm
56 = 7•8
56 = 56
This circuit is correct.

Bottom-right circuit:
V = 20V, I = 5A, R = 4ohm
20 = 5•4
20 = 20
This circuit is correct.

The following circuits are correct: top-left, bottom-left, and bottom-right.
Amiraneli [1.4K]3 years ago
5 0

Answer:

the top left and the bottom left and the bottom right

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the electrons shared between the oxygen and hydrogen atoms spend more time around the oxygen atom nucleus than around the hydrogen atom nucleus

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If an object were released in space far away from planted or stars and given an initial momentum, describe what would happen to
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3 years ago
Read 2 more answers
The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
WINSTONCH [101]

Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

Initial K.E = K.E1 = 10000J

Final K.E = K.E2 = 2000J

∆K.E= 10000J - 2000J = 8000J

From equation 1,

∆K.E = ∆T.E

∆T.E = 8,000J

thermal energy gain by brakes = 8,000J

8 0
2 years ago
Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri
Lady bird [3.3K]

Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

\int dW = \int_0^{0.1} k.x dx

W = \int_0^{0.1} k.x dx

W = k[\dfrac{x^2}{2}]_0^{0.1}

10 = k\dfrac{0.1^2}{2}

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

W = \int_{0.1}^{0.2} 2000 x dx

W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

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2 years ago
Examples of buoyancy
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