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2 years ago

Calculate the energy of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49x10 to the 14 th power Hz

1 answer:

4 0

For this problem, we have to use the Planck's equation.

E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·<span>s
v is the frequency in Hz or s</span>⁻¹<span>

Applying the equation, the answer would be:

E = (</span>6.626×10⁻³⁴ J·s)(5.49×10¹⁴ s⁻¹)
<em>E = 3.64×10⁻¹⁹ J</em>

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How is the separation of dna like a zipper

Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.

The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

3 0

2 years ago

I need help plz with the first question plz

Cloud [144]

Ok so put it in order

7 0

3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant

Vanyuwa [196]

<h3>Answer:</h3>

Excess Reagent = NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

2 moles NBr₃ reacts with = 3 moles of NaOH

So,

40 moles of NBr₃ will react with = X moles of NaOH

Solving for X,

X = (40 mol × 3 mol) ÷ 2 mol

X = 60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0

2 years ago

A sample of salt (sodium chloride) is placed on the tip of a platinum wire. When the sample is heated on blue flame the flame tu

gulaghasi [49]

So platinum is a transition metal. In general transition metals are reducers, which means they can give the electrons they have, to the sodium atoms. Also in chemistry we look at sub orbitals rather that shells(2,8,8). So due to the energy from heat, the d orbital split as electrons move to a higher energy level. Some of the electrons are given to the sodium ions and therefore the flame changes colour to yellow.
The excitation of the electrons is caused by them getting energy and so moving up an energy level. This energy is released and the electron returns to it's original state. The energy released, however, does not release in the same direction, but in different/various directions. Therefore the colour of the light changes as some energy is released in the surrounding.

8 0

3 years ago

How many moles are present in

olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b) There are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of $N_{2}$ is 28 g/mol so its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol$

So, there are 0.428 moles present in 12 g of $N_{2}$ molecule.

(b). According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ atoms.

Therefore, moles present in $12.044 \times 10^{23}$ particles are calculated as follows.

$Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol$

So, there are 2 moles present in $12.044 \times 10^{23}$ particles of oxygen.

4 0

2 years ago