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snow_lady [41]
2 years ago
13

Based on the type or types of intermolecular forces, predict the substance in each pair that has the higher boiling point Match

the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer Reset Help stronger dispersion forcesG Given the molecules propane (C3Hs) and n-butane (C4H10), Г- has the higher boiling point mainly due to n-butane (C,H Given the molecules diethyl ether (CH3 CH2OCH2 CHs) and 1-butanol (CH3 CH2CH2 CH2OH) higher boiling point mainly due to 1-butanel CH,CH, CH,CH,OH) diethyl ether (CH CH,OCH CH, has the propane (C, H ts greater melar mass
Chemistry
1 answer:
rosijanka [135]2 years ago
5 0

Answer:

C4H10 has a higher boiling point due to stronger dispersion forces

1-butanol has the greater boiling point mainly due to hydrogen bonding influences

Explanation:

If we consider propane and n-butane, we discover that they are both alkanes. However, the magnitude of dispersion forces in alkanes depends on the length of the carbon chain. The greater the length of the carbon chain is greater in n-butane than in propane. The greater the chain length, the greater the magnitude of dispersion forces and the greater the boiling point. Hence, n-butane has a higher boiling point than than propane.

Also, if we compare the boiling points of 1-butanol to that of diethyl ether, we will discover that 1-butanol has a higher boiling point mainly due to intermolecular hydrogen bonding influences.

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10g of hyrogen react with excess of oxygen gas according to the equation:
Degger [83]

Answer:

Volume of O₂ = 56 dm³

mass of water vapors (H₂O) = 90 g

Explanation:

Data Given:

mass of Oxygen = 10 g

Volume of Oxygen = ?

mass of the water vapor = ?

Reaction Given:

                 2H₂+O₂---->2H₂O

Solution:

First we have to look at the reaction for the information required

                 2H₂   +  O₂  -------> 2H₂O

               2 mol    1mol           2 mol

now convert moles to grams

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of O₂ = 2(16) = 32 g/mol

molar mass of H₂0 = 2(1) + 16 = 18 g/mol

So the masses will be

                      2H₂          +              O₂        ------->      2H₂O

                2 mol (2 g/mol)      1mol (32 g/mol)         2 mol (18 g/mol)

                      4 g                            32 g                           36 g

So now we know that

4 g of hydrogen combine with 32 g of Oxygen and give 36 g of water vapors.

By using above information

First we find the volume of Oxygen:

For this first we find mass and then moles of Oxygen

As we know

if 4 g of hydrogen combine with 32 g of Oxygen then how much oxygen will react with 10 g of hydrogen

Apply unity formula

                        4 g of hydrogen H₂ ≅ 32 g of Oxygen O₂

                         10 g of hydrogen H₂ ≅ X g of Oxygen O₂    

by doing Cross multiplication

                         g of Oxygen O₂   = 32 g x 10 g / 4 g

                         g of Oxygen O₂   = 80 g

So,                  

mass of oxygen = 80 g

now find moles of oxygen

formula used:

            no. of moles = mass in grams/ molar mass . . . . . . (1)

Put values in above equation 1

            no. of moles = 80 g / 32 g/mol

             no. of moles = 2.5

Now to find volume of oxygen

Formula used

 Volume of O₂ = no. of moles x molar volume (22.4 dm³/ mol) . . . . . . (2)

Put values in equation 2

             Volume of O₂ = 2.5 moles x 22.4 dm³/mol

            Volume of O₂ = 56 dm³

______________________

Now to find mass of water vapors

As we now

if 4 g of hydrogen produce 36 g of water vapors then how much water vapor will produce from 10 g of hydrogen

Apply unity formula

                        4 g of hydrogen H₂ ≅ 36 g of water vapors (H₂O)

                         10 g of hydrogen H₂ ≅ X g of water vapors (H₂O)  

by doing Cross multiplication

                         g of water vapors (H₂O) = 36 g x 10 g / 4 g

                         g of water vapors (H₂O)   = 90 g

So,                  

mass of water vapors (H₂O) = 90 g

5 0
2 years ago
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