Answer:Reliability
Explanation:
Reliability of a test refers to how consistently a test measures a characteristic under the same conditions.
Reliability can be defined as the degree of consistency of which a chemical test gives a similar result. measure. A test is said to be highly reliable when it gives the same repeated result under the same conditions of measure.
But when a test gives different results under the same condition of measure it has a low reliability.
Hence, If a test yields consistent results every time it is used, it has a high degree of reliability.
Answer:
I would say A. I'm no expert, but it can't be C obviously, and I think wind would hit all of it, wearing off the top as well like the great pyramids. B would be my next choice, but A i think would be best.
Answer:
1.414 Moles
Solution:
Data Given:
Mass of MgS₂O₃ = 193 g
M.Mass of MgS₂O₃ = 136.43 g.mol⁻¹
Moles = ?
Formula Used:
Moles = Mass ÷ M.Mass
Putting values,
Moles = 193 g ÷ 136.43 g.mol⁻¹
Moles = 1.414 mol
Answer:
a) = 0.704%
b) = 1.30%
c) = 2.60%
Explanation:
Given that:
= 
For Part A; where Concentration of A = 0.270 M
Percentage Ionization(∝) 



percentage% (∝) = 
= 0.704%
For Part B; where Concentration of B =
M



percentage% (∝) = 0.0130 × 100%
= 1.30%
For Part C; where Concentration of C= 



percentage% (∝) = 0.02608 × 100%
= 2.60%
Answer:
Hydrogen has one proton, two neutrons and one electron.
Explanation:
I hope this helps.