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slava [35]
4 years ago
5

Luster, conductivity, and malleability are physical properties of metals. What makes these properties different from chemical pr

operties?
A. Physical properties relate to elements rather than compounds.

B. Physical properties appear only after a chemical change occurs.

C. Physical properties can be observed without attempting to change the identity of the substance.

D. Physical properties describe elements in the solid state rather than in the liquid or gas state.
Chemistry
1 answer:
Alla [95]4 years ago
3 0

Answer:

C

Explanation:

A Is false because physical properties can relate to any chemical substance.

B Is false because physical properties are apparent wether a chemical change has occurred or not.

C Is correct because physical properties can be observed without making a chemical change to the substance, chemical properties cause physical properties but a chemical change is not needed to observe a physical property.

D Physical properties describe compounds in all phases of matter.

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At 293 K, methanol has a vapor pressure of 97.7 Torr and ethanol has a vapor pressure of 44.6 Torr. What would be the vapor pres
Bad White [126]

Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

p_1=x_1p_1^0 and p_2=x_2P_2^0

where, x = mole fraction in solution  

p^0 = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2p_{total}=x_Ap_A^0+x_BP_B^0

moles of ethanol=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{80g}{46g/mol}=1.7moles

moles of methanol= \frac{\text{Given mass}}{\text {Molar mass}}=\frac{97g}{32g/mol}=3.0moles

Total moles = moles of ethanol + moles of methanol = 1.7 +3.0 = 4.7

x_{ethanol}=\frac{1.7}{4.7}=0.36,

x_{methanol}=1-x_{ethanol}=1-0.36=0.64

p_{ethanol}^0=44.6torr

p_{methanol}^0=97.7torr

p_{total}=0.36\times 44.6+0.64\times 97.7=78.3torr

Thus the vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

8 0
4 years ago
Which of the following best describes foliated metamorphic rocks?
nekit [7.7K]

Answer:

It's C because Metamorphic rocks were once igneous rocks. And, because Gneiss which is a Metamorphic rock has crystals inside of it.

3 0
3 years ago
All of the above
Natalka [10]
The plants without any fertiliser could be the control, to see what the change in the independent variable (fertiliser) does to the growth of the plant (dependant variable).

Hope that helps.
8 0
3 years ago
Consider the following oxides: SO2, Y2O3, MgO, Cl2O, and N2O5. How many are expected to form acidic solutions in water? Consider
Snowcat [4.5K]

Answer:

Three of the five oxides are expected to form acidic solutions in water

Explanation:

We have different types of oxides : Acidic oxides, Basic oxides, Amphoteric oxides, Peroxides and Higher oxides.

Only acidic oxides will dissolve in water to give an acidic solution.

Considering the given oxides carefully,

  • SO2 will dissolve in water to produce H2SO3 which is acidic.

  • Y2O3 will dissolve in water to produce Yttrium(III) hydroxide which is basic.

  • MgO will dissolve in water only to produce Mg(OH)2 which is also basic.

  • Cl2O dichlorine mono oxide will dissolve in water to produce HClO which is acidic.

  • N2O5 will dissolve in water to produce HNO3 which is also acidic.

5 0
3 years ago
Balloon A started with a volume of 1.76 L. The temperature of the room the balloon was in was 295 K. The balloon was heated to a
valentina_108 [34]

Answer:

V₂ = 1.5 L

Explanation:

Given data:

Initial volume of balloon = 1.76 L

Initial temperature = 295 K

Final temperature = 253.15 K

Final volume = ?

Solution:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.76 L ×253.15 K / 295 K

V₂ = 445.54 L.K /295 K

V₂ = 1.5 L

4 0
4 years ago
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