2 years ago

A water gun fires 5 squirts per second. The speed of the squirts is 15 m/s.

Physics

1 answer:

stira [4]2 years ago

4 0

Answer: 3.75 m

Explanation:

5 squirts in 1 second

So, 1 squirt in 1/5 second which is 0.2 second.

The difference in timing of two consecutive squirt is 0.2 second, so

time (t) = 0.2 s.

speed (s) = 15 m/s

Distance of separation (d) = ?

Now, formula for distance is

d = s × t

d = 15 × 0.2

d = 3.75 m

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Read 2 more answers

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns

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Complete Question

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns.

The output from the secondary coil is 12 V

Answer:

The value is $N_s = 21 \ turns$

Explanation:

From the equation we are told that

The input voltage is $V_{in} = 120 \ V$

The number of turns of the primary coil is $N_p = 210 \ turn$

The output from the secondary is $V_o = 12V$

From the transformer equation

$\frac{N_p}{V_{in}} =\frac{N_s}{V_o}$

Here $N_s$ is the number of turns in the secondary coil

=> $N_s = \frac{N_p}{V_{in}} * V_s$

=> $N_s = \frac{210}{120} * 12$

=> $N_s = 21 \ turns$

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