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natulia [17]
3 years ago
6

The head of a rattlesnake can accelerate at 40 m/s2 in striking a victim. If a car could do as well, how long would it take to r

each a speed of 73 km/h from rest?
Physics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

Time taken will be 0.5069 sec    

Explanation:

Acceleration of the car is given a=40m/sec^2

Let the car starts from the rest so initial velocity of the car u=0m/sec

Final velocity v = 73 km/hr

So 7km/hr=\frac{73\times 5}{18}=20.277m/sec

From first equation of motion v = u+at

So 20.277=0+40\times t

t = 0.5069 sec

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Can someone help me?
Alik [6]

Answer:

Resultant = 3.05N

Explanation:

r =  \sqrt{{5}^{2} + 5^{2} - 2(5)(5) \cos(120) }

r =  \sqrt{25 + 25 - 50(0.8142)}

r =  \sqrt{50 - 40.71}  =  \sqrt{9.29}

r = 3.05

6 0
2 years ago
an airplane is traveling at an altitude of 31,360. a box of supplies is driped from the cargo hold how long will it take to reac
VMariaS [17]

Answer: 1,600 seconds

Explanation:

31,360/9.8 = 3,200.

Then divide 3,200/2 = 1,600

7 0
2 years ago
Compare the gravity between these pairs, each consisting of an Earth-like planet and its star. You are given the mass of the pla
Maru [420]

Answer:

The answer is below

Explanation:

Newton's law of gravity states that the force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The law is expressed by the formula:

F=G\frac{m_1m_2}{r^2} \\\\Where\ F=force,G=gravitational\ constant, m_1\ and\ m_1=mass\ of\ objects,r\ =distance\ between \ the\ two\ objects.

The masses and distances for this question is in common units, Therefore the result would be in ratios

a) 4 MEarth / 2 MSolar / 3 AU

The force (F) = (4 * 3) / 3² = 4/3

b) 1 MEarth / 1 MSolar / 1 AU

The force (F) = (1 * 1) / 1² = 1

c) 1 MEarth / 2 MSolar / 2 AU

The force (F) = (1 * 2) / 2² = 1/2

6 0
2 years ago
A small ferryboat is 3.90 m wide and 6.30 m long. when a loaded truck pulls onto it, the boat sinks an additional 5.00 cm into t
Leya [2.2K]
When the truck's weight is added to the boat, the boat sinks 5 cm deeper,
and displaces additional water whose weight is equal to the weight of the
truck.

The volume of the additional displaced water is

             (3.9 m) x (6.3 m) x (5.0 cm)

         =  (3.9 m) x (6.3 m) x (0.05 m)  =   1.2285 m³ .

The weight of that much water is the weight of the truck.

          Mass of 1 liter of water  =  1 kilogram

          1.2285 m³  =  1,228.5 liters  =  1,228.5 kg of water.

          Weight = (mass) x (gravity)

                      = (1,228.5 kg) x (9.8 m/s²)  =  12,039 Newtons.

                                                                  (about 2,708 pounds) 

6 0
3 years ago
A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have? The car has J of kinetic
konstantin123 [22]
The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the mass of the object and v its velocity. 

The car in this problem has a mass of m=600 kg and a velocity of v=10 m/s, therefore if we put these numbers into the equation, we find the kinetic energy of the car:
K= \frac{1}{2}mv^2= \frac{1}{2}(600 kg)(10 m/s)^2=30000 J
5 0
2 years ago
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