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natulia [17]
4 years ago
6

The head of a rattlesnake can accelerate at 40 m/s2 in striking a victim. If a car could do as well, how long would it take to r

each a speed of 73 km/h from rest?
Physics
1 answer:
kvv77 [185]4 years ago
3 0

Answer:

Time taken will be 0.5069 sec    

Explanation:

Acceleration of the car is given a=40m/sec^2

Let the car starts from the rest so initial velocity of the car u=0m/sec

Final velocity v = 73 km/hr

So 7km/hr=\frac{73\times 5}{18}=20.277m/sec

From first equation of motion v = u+at

So 20.277=0+40\times t

t = 0.5069 sec

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What are the cahnges that a force can bring out on a body ? <br><br><br>Give examples
djyliett [7]
Hi Pupil Here is your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



1 The shape of the Body

Example : The shape of the ball lying on a floor can be changed by pressing it.


2 Direction of the Body

Example : The direction of motion of moving ball can be changed by hitting it with a bat.


3 The speed of the Body

Example : A ball at rest can be set in motion if force is applied only


4. Size of the Body

Example : The length of a spring tied and on one end can be increased by pulling it.




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Hope this helps .......
5 0
3 years ago
Read 2 more answers
As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
astraxan [27]

Answer:

3.6 x 10⁶ Pa

Explanation:

A = Area of the heel = 1.50 cm² = 1.50 x 10⁻⁴ m²

m = mass of the woman = 55.0 kg

g = acceleration due to gravity = 9.8 m/s²

Force of gravity on the heel is given as

F = mg

Inserting the values

F = (55) (9.8)

F = 539 N

Pressure exerted on the floor is given as

P = \frac{F}{A}

P = \frac{539}{1.5\times 10^{-4}}

P = 3.6 x 10⁶ Pa

6 0
3 years ago
The energy released by the exploding gunpowder in a cannon propels the cannonball forward. Simultaneously, the cannon recoils. T
Lelechka [254]

Answer:

the launched cannonball

Explanation:

4 0
3 years ago
How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium
Minchanka [31]

The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

<h3>Pressure and temperature at equilibrium </h3>

The relationship between pressure and temperature can be used to determine the height risen by the water.

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where;

  • V₁ = AL
  • V₂ = A(L - y)
  • P₁ = Pa
  • P₂ = Pa + ρgh
  • T₁ = 20⁰C = 293 K
  • T₂ = 10⁰ C = 283 k

\frac{PaAL}{T_1} = \frac{(P_a + \rho gh)A(L-y)}{T_2} \\\\\frac{PaL}{T_1} = \frac{(P_a + \rho gh)(L-y)}{T_2} \\\\L-y = \frac{PaLT_2}{T_1(P_a + \rho gh)} \\\\y = L (1 - \frac{PaT_2}{T_1(P_a + \rho gh)})\\\\y = 4.2(1 - \frac{101325 \times 283}{293(101325\  +\  1000 \times  9.8 \times  100)} )\\\\y = 3.8 \ m

Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

The complete question is below:

A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?

Learn more about thermal equilibrium here: brainly.com/question/9459470

#SPJ4

3 0
2 years ago
11.
jolli1 [7]
<h3>Reducing Surface Area.</h3>

If the surface area becomes smaller, the pressure becomes larger.

8 0
3 years ago
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