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seropon [69]
4 years ago
5

define a compound machine in comparison to a simple machine. name a simple machine and a compound machine

Physics
1 answer:
Reika [66]4 years ago
6 0
A compound machine is a machine composed of two or more simple machines. Common examples are bicycles, can openers and wheelbarrows. Simple machines change the magnitude or direction of a force without any motor. <span>Simple machines are generally easy to understand and work on simple principles. They include such things as levers, which grant mechanical advantage, and wedges, which redirect relative motion, and wheels of various sorts, from pulleys to bicycle gears. </span>
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Lifting book over your head is what type of energy
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potential energy

Explanation:

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Why do the waves have different speeds in different layers of Earth's surface?
Genrish500 [490]

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Material's density

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6 0
2 years ago
A 25 kg bear slides, from rest, 12 m down a lodgepole pine tree, moving with a speed of 5.6 m/s just before hitting the ground.
Anuta_ua [19.1K]

Answer:

(A) -2940 J

(B) 392 J

(C) 212.33 N

Explanation:

mass of bear (m) = 25 kg

height of the pole (h) = 12 m

speed (v) = 5.6 m/s

acceleration due to gravity (g) = 9.8 m/s

(A) change in gravitational potential energy (ΔU) = mg(height at the bottom- height at the top)

height at the bottom = 0

         = 25 x 9.8 x (0-12) = -2940 J

(B) kinetic energy of the Bear (KE) = 0.5mv^{2}

           = 0.5 x 25 x 5.6^{2}  = 392 J

(C) average frictional force = \frac{change in thermal energy}{height} = \frac{-(ΔKE+ΔU)}{h}

  • change in KE (ΔKE) = initial KE - final KE
  • ΔKE = 0.5mv^{2} - 0.5mvf^{2}            
  • when the Bear reaches the bottom of the pole, the final velocity (Vf) is 0, therefore the change in kinetic energy becomes  ΔKE = 0.5x25x5.6^{2} - 0 = 392 J

 \frac{-(ΔKE+ΔU)}{h}[/tex] = \frac{-(392 + (-2940))}{12}

=  \frac{(-392 + 2940)}{12} = 212.33 N

5 0
3 years ago
Why do we use microwaves to communicate berween earth and satellites
nlexa [21]
It’s frequency is high and microwaves can pass through the atmosphere of the Earth.
7 0
4 years ago
Read 2 more answers
A total of 750 j of work was done when a force of 125 n was exerted on a box to move it. how far was the box moved?
Slav-nsk [51]
Work = Force times Distance
W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
d = 750/125
d = 6

The box moved a distance of 6 meters.
3 0
3 years ago
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