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enot [183]
2 years ago
12

PHYSICSSS PLEASE HELP

Physics
1 answer:
Aleonysh [2.5K]2 years ago
3 0

Answer:

1. 10.5 Kg

2. s/g

Explanation:

1. Determination of the mass of gasoline

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:

Density = mass / volume

With the above formula, we can obtain the mass of the gasoline as follow:

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

Density = mass / volume

0.7 = Mass of gasoline / 15

Cross multiply

Mass of gasoline = 0.7 × 15

Mass of gasoline = 10.5 Kg

2. Density has various units some are listed below:

I. Kilogram per litre (Kg/L)

II. Kilogram per cubic metre (Kg/m³)

III. Milligram per millilitre (mg/mL)

IV. Gram per millilitre (g/mL)

V. Gram per cubic centimetre (g/cm³)

Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.

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Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

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When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

u^2=u_x^2+u_y^2

Where, u_x\ and\ u_y are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1

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H=\frac{u_y^2}{2g}

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m

Therefore, the maximum height reached is 4.63 m.

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