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Below is the solution:
Output work = 108 J.
<span>Input work = 120 J </span>
<span>Efficiency = 108/120 = 9/10 = 90% </span>
<span>(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)</span>
Answer:
Electric field at a distance of 1.45 cm will be 
Explanation:
We have given the distance d = 1.45 cm = 0.0145 m
And the potential difference 
There is a relation between potential difference and electric field
Electric field at a distance d due to a potential difference is given by
, here E is electric field, V is potential difference and d is distance
So 
The shortest and straight ones
The force equals the coefficient of static friction times the weight. Use gravity g=9.8 m/s^2
0.43*40*9.8=16.856 N
Answer:
The force that happens between two particles with mass
