The answer is 4.41x10^1 m.
Explanation:
You would use this formula to calculate it
λ = C/f
Where,
λ (Lambda) = Wavelength in meters
c = Speed of Light (299,792,458 m/s)
f = Frequency
So we have the frequency, 68 Hz, and we have the speed of light. Now we put it into the equation and it will look like this:
λ= (299,792,458 m/s) / (68 Hz)
λ= 4.41x10^1
Answer:
238,485 Joules
Explanation:
The amount of energy required is a summation of heat of fusion, capacity and vaporization.
Q = mLf + mC∆T + mLv = m(Lf + C∆T + Lv)
m (mass of water) = 75 g
Lf (specific latent heat of fusion of water) = 336 J/g
C (specific heat capacity of water) = 4.2 J/g°C
∆T = T2 - T1 = 119 - (-20) = 119+20 = 139°C
Lv (specific latent heat of vaporization of water) = 2,260 J/g
Q = 75(336 + 4.2×139 + 2260) = 75(336 + 583.8 + 2260) = 75(3179.8) = 238,485 J
Answer:
i think d maybe correct me if im wrong
Explanation:
Answer: i think B
Explanation: i may be wrong sorry :(
Answer:
6) λ = 0.84 × 10⁻⁸ m
7) λ = 0.84 × 10⁻⁶ m
Explanation:
6) Given data:
Wavelength of photon = ?
Frequency of photon = 3.56 × 10¹⁶ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 3.56 × 10¹⁶ Hz × λ
λ = 3×10⁸ m/s / 3.56 × 10¹⁶ s⁻¹
λ = 0.84 × 10⁻⁸ m
7) Given data:
Wavelength of photon = ?
Frequency of photon = 6.15 × 10¹⁴ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 6.15 × 10¹⁴ Hz × λ
λ = 3×10⁸ m/s / 6.15 × 10¹⁴ Hz s⁻¹
λ = 0.84 × 10⁻⁶ m