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3 years ago

30 POINTS PLZ HELP!!!!

Physics

2 answers:

makkiz [27]3 years ago

7 0

the answer to this is true.

i know this cuz im smart

Elanso [62]3 years ago

5 0

the answer to this is true.

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A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time

baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

$i = \frac{q}{t}$

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

$i = increased$

So correct answer will be

B. The current increases.

4 0

4 years ago

how does the presence of carbon dioxide in venus’ atmosphere cause the average surface temp on venus to be higher than the avera

soldier1979 [14.2K]

It is because carbon dioxide traps the solar radiation which then warms up the atmosphere, not allowing the radiations to get deflected back in the outer space.. that's what is happening to our own planet the greenhouse effect.. which is also increasing the GLOBAL Temp of our planet too

3 0

4 years ago

Superman takes 8 seconds to stop a runway train over a distance of 58 m using a power of

elena-14-01-66 [18.8K]

Answer:

Workdone = 600 Kilojoules

Explanation:

Given the following data:

Time = 8 seconds

Power = 75,000 Watts

Distance = 58 m

To find the work done;

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

$Power = \frac {Energy}{time}$

Thus, work done is given by the formula;

Workdone = power * time

Workdone = 75000 * 8

Workdone = 600,000 = 600 KJ

5 0

3 years ago

A ball having a mass of 130 g strikes a wall with a speed of 6.5 m/s perpendicular to the wall and rebounds with only 42% of its

RoseWind [281]

Answer

given,

mass of ball = 130 g = 0.13 kg

speed = 6.5 m/s

t = 9.5 ms = 0.0095 s

rebound with 42 % of initial kinetic energy

a) $\dfrac{1}{2}mv_2^2 =0.42\times \dfrac{1}{2}mv_1^2$

$v_2^2 =0.42\times (6.5)^2$

v₂ = 4.212 m/s

b) impulse is equal to change in momentum

$I = m (v_1-v_2)$

$I = 0.13\times(6.5 -(-4.21))$

I = 1.393 kg m/s

c) Force = $\dfrac{I}{t}$

= $\dfrac{1.393}{0.0095}$

F = 146.63 N

4 0

3 years ago

Cold air masses tend to originate from: Question 3 options: tropical areas an area where it's wintertime an area where it's summ

suter [353]

Answer:

Polar areas

Explanation:

From what I know Arctic, Antarctic, and polar air masses are cold. Polar (cold), Arctic (very cold), Equatorial (warm and very moist), and Tropical (warm).

With the options you gave, you can immeditaly elimate 1. tropical areas and 2. an area where its summertime.

Your then left with two options 1. an area where its wintertime and 2. polar areas

I then concluded that cold air masses tend to originate from POLAR AREAS.

6 0

2 years ago

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